In a vacuum, all objects fall at the same rate. Meaning that the 100 kg ball will fall at the same speed as the 10 kg ball. Assuming that both objects share the same starting acceleration, they will keep that acceleration until the fall is stopped.
In other words, your answer is the first one, Both objects will accelerate at 9.8 m/s
This took me a short while to figure out, but I am still not entirely sure if this is correct, this is just from my basic understanding of Newtons Second Law of Motion.
You have a 4kg cart with a force of 20N acting on it.
The formula for working out the acceleration is.
a=Fnet÷mass
Substitute in the information.
a=20N÷4kg
Now you solve it to give you.
a=5m/s
So now what you should be able to do is figure out that after 10 seconds the cart travelling at 5m/s would have travelled 10 metres.
This is achieved by finding out how many 5's go into 10 which is 2.
So you do 5×2 which equals 10.
The 4kg cart has travelled 10 meters in 10 seconds with a force of 20N acting upon it.
I hope that this has helped you.
The circular shape allows the tire to roll easily with the least amount of bumps or jolts
Answer:
Explanation:
Given
winning car accelerates with a and its final velocity is v
considering they both start from rest
time taken by winning car is
v=u+at
where u=initial velocity
a=acceleration
t=time
Now loosing car is accelerating with 
Distance traveled by loosing car in time t
Thus distance d traveled by loosing car is given by
