1. If we increase the distance to twice it's original value, the light intensity is reduced by one-fourth, the light intensity would be:
I0/4
2. rms magnetic field is inversely proportional to distance, so the new rms magnetic field would be:
B0/2
3. average energy density is inversely proportional to the square of the distance, so the new average energy density is:
E0/4
Answer:
The torque on the loop is
Nm
Explanation:
Given:
Current
A
Magnetic field
T
Area of loop

Angle between magnetic field and area vector
21°
Form the formula of torque in case of magnetic field,
г
Where
magnetic moment

г 
г 
г
Nm
Therefore, the torque on the loop is
Nm
Answer:
1750 Joules.
Explanation:
Work done = force * distance
= 7 * 250
= 1750 Joules.
Centripetal acceleration points from the object toward the center of the circular path it's traveling.
Answer:
Magnitude of static friction force is 70 sin40° = 44.99 N.
No, it is not necessary that it is maximum static friction.
Normal force is equal to 70 cos40° = 53.62 N.
Explanation:
We apply newton law of moton equation along the plane and perpendicular to plane;
Along the plane,
70 sin 40° =
---------------(1)
70 cos 40° = N --------------(2)
= μN -----------------(3)
So, it depends on the value of μ that the friction is maximum or not .