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marshall27 [118]
3 years ago
7

The standard kilogram is a platinum-iridium cylinder 39.0 mm in height and 39.0 mm in diameter. What is the density of the mater

ial?
Physics
1 answer:
KengaRu [80]3 years ago
7 0

Density is mass per unit of volume, usually measured in g/cm³. So first determine the volume of the cylinder:

<em>v</em> = <em>π</em> <em>r </em>² <em>h</em> = <em>π</em> ((39.0 mm) / 2)² (39.0 mm)

<em>v</em> = 59,319/4 <em>π</em> mm³ ≈ 46,589 mm³ ≈ 46.589 cm³

Then the density is

<em>ρ</em> = <em>m</em> / <em>v</em>

<em>ρ</em> = (1 kg) / <em>v</em> = (1000 g) / <em>v</em>

<em>ρ</em> ≈ 21.464 g/cm³

Or, if you want to preserve the given units, that's

<em>ρ</em> ≈ 0.00002146 kg/mm³

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Explanation:

In order to estimate the distance traveled by a lightening flash in kilometers, we follow these simple steps:

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Use the definition of scalar product, a overscript right-arrow endscripts times b overscript right-arrow endscripts = ab cos θ,
makkiz [27]

Answer: \theta=cos^{-1}0.991=7.69^o

The following vectors have been given: \vec{a}=3.0\widehat{i}+3.0\widehat{j}+3.0\widehat{k}\\ \vec{b}=5.0\widehat{i}+7.0\widehat{j}+6.0\widehat{k}

The angle between these two vectors can be found by:

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\vec{a}.\vec{b}=a_xb_x+a_yb_y+a_zb_z\\ \vec{a}.\vec{b}=3\times5+3\times7+3\times6=15+21+18=54

||\vec{a}||=\sqrt{3^2+3^2+3^2}=\sqrt{27}\\ ||\vec{b}||=\sqrt{5^2+7^2+6^2}=\sqrt{110}

cos\theta=\frac{54}{\sqrt{27}\times\sqrt{110}}\\=0.991\\ \Rightarrow \theta=cos^{-1}0.991=7.69^o

7 0
3 years ago
A 5.6 g marble is fired vertically upward using a spring gun. The spring must be compressed 6.4 cm if the marble is to just reac
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The length of a simple pendulum is 0.760 m, the pendulum bob has a mass of 365 grams, and it is released at an angle of 12.0o to
Allushta [10]

Answer:

0.572 Hz

Explanation:

given,

length of simple pendulum, l = 0.76 m

mass of the bob, m = 365 g = 0.365 Kg

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f = \dfrac{1}{2\pi}\sqrt{\dfrac{g}{L}}

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f = \dfrac{1}{2\pi}\times 3.59

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