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marshall27 [118]
3 years ago
7

The standard kilogram is a platinum-iridium cylinder 39.0 mm in height and 39.0 mm in diameter. What is the density of the mater

ial?
Physics
1 answer:
KengaRu [80]3 years ago
7 0

Density is mass per unit of volume, usually measured in g/cm³. So first determine the volume of the cylinder:

<em>v</em> = <em>π</em> <em>r </em>² <em>h</em> = <em>π</em> ((39.0 mm) / 2)² (39.0 mm)

<em>v</em> = 59,319/4 <em>π</em> mm³ ≈ 46,589 mm³ ≈ 46.589 cm³

Then the density is

<em>ρ</em> = <em>m</em> / <em>v</em>

<em>ρ</em> = (1 kg) / <em>v</em> = (1000 g) / <em>v</em>

<em>ρ</em> ≈ 21.464 g/cm³

Or, if you want to preserve the given units, that's

<em>ρ</em> ≈ 0.00002146 kg/mm³

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Answer:

W_n_e_t=7.648512 \approx 7.6J

K.E=0.8J

v=0.7844645406 \approx 0.78m/s

Explanation:

From the question we are told that

Mass of pitcher   M= 2.6kg

Force on pitcher f=8.8N

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Coefficient of friction \mu=0.28

a)Generally frictional force is mathematically given by

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F=0.28*2.6*9.8

F=7.1344N

Generally work done on the pitcher is mathematically given as

W_n_e_t=W_f+W_F

W_f=8.8*0.48=>4.224N\\W_F=7.1344*0.48=>3.424512N

W_n_e_t=4.224-3.424512

W_n_e_t=0.799488\approx 0.8J

b)Generally K.E can be given mathematically as

K.E= W_n_e_t

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K.E=0.8J

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K.E=1/2mv^2

0.8=1/2mv^2

Velocity as subject

v=\sqrt{\frac{K.E*2}{m} }

v=\sqrt{\frac{0.8*2}{2.6} }

v=0.7844645406 \approx 0.78m/s

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Explanation:

Given that,

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(a) The wavelength of this very low frequency electromagnetic wave is given by using relation as :

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\lambda=\dfrac{c}{f}

\lambda=\dfrac{3\times 10^8\ m/s}{60\ Hz}

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(b) As its can be seen that the wavelength of this wave is very high. It shows that it is a radio wave.

(c) The relation between the maximum magnetic field strength and maximum electric field strength is given by :

B_0=\dfrac{E_0}{c}\\\\B_0=\dfrac{11.6\times 10^3}{3\times 10^8}\\\\B_0=3.86\times 10^{-5}\ T

So, the maximum magnetic field strength is 3.86\times 10^{-5}\ T.

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