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aalyn [17]
3 years ago
9

The exact speed of an object in a specific instant is?

Physics
2 answers:
GarryVolchara [31]3 years ago
3 0
Im not so sure but it should be the
instantaneous speed 

sertanlavr [38]3 years ago
3 0
Instantaneous Speed.
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Who would be most likely to analyze a tablet with cuneiform to determine what goods were traded by the merchants of Ur?
mars1129 [50]
 I think your answer would Be A. Because historians mostly study written documents, while archaeologists uncover fossils and buildings.
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3 years ago
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By applying the third law of motion, which force is greater when you push on a wall? Your force, the wall’s force, your force an
o-na [289]

Hello!

By applying the third law of motion, your force and the wall's force are equal.

I hope this helps you! Have a great day!

- Mal

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A 150 kg car hits a wall with 45 N of force, what was its acceleration?​
alisha [4.7K]

Answer:

a = 0.3 m/s²

Explanation:

Given: 45 N, 150 kg

To find: a

Formula: a = \frac{F}{m}

Solution: To find a, divide the force by the weight  

A = F ÷ m

=  45 ÷  150

= 0.3 m/s²

Newtons are derived units, equal to 1 kg-m/s². In other words, a single Newton is equal to the force needed to accelerate one kilogram one meter per second squared.

4 0
3 years ago
In a crash or collision, why is it advantageous for an occupant to extend the time during which the collision is taking place?
Veseljchak [2.6K]

Answer:

Explanation:

During a car collision momentum of vehicle ceases within a fraction of seconds so Force due to the impulse is huge.

Impulse is defined as the product of average force and time. If we can increase the period of collision for the same impulse then the average force imparted will be less.

If we can increase the time period then damage due to collision will be less.

                     

3 0
2 years ago
The cornea behaves as a thin lens of focal lengthapproximately 1.80 {\rm cm}, although this varies a bit. The material of whichi
Keith_Richards [23]

Answer:

Explanation:

  a )

from lens makers formula

\frac{1}{f} =(\mu-1)(\frac{1}{r_1} -\frac{1}{r_2})

f is focal length , r₁ is radius of curvature of one face and r₂ is radius of curvature of second face

putting the values

\frac{1}{1.8} =(1.38-1)(\frac{1}{.5} -\frac{1}{r_2})

1.462 = 2 - 1 / r₂

1 / r₂ = .538

r₂ = 1.86 cm .

= 18.6 mm .

b )

object distance u = 25 cm

focal length of convex lens  f  = 1.8 cm

image distance  v   = ?

lens formula

\frac{1}{v} - \frac{1}{u} = \frac{1}{f}

\frac{1}{v} - \frac{1}{-25} = \frac{1}{1.8}

\frac{1}{v} = \frac{1}{1.8} -\frac{1}{25}

.5555 - .04

= .515

v = 1.94 cm

c )

magnification = v / u

= 1.94 / 25

= .0776

size of image = .0776 x size of object

= .0776 x 10 mm

= .776 mm

It will be a real image and it will be inverted.

 

5 0
2 years ago
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