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3 years ago

Find the domain and range of the function represented by the graph. Select all that apply.

Mathematics

1 answer:

Sveta_85 [38]3 years ago

8 0

Answer:

Domain: [-2, 0, 2, 4]

Range: [3]

Step-by-step explanation:

The domain of the function are all values of x that are plotted on the horizontal axis (x-axis), while the range are the corresponding y-values plotted on the vertical axis (y-axis).

Therefore,

Domain of the function = [-2, 0, 2, 4]

Range of the function = [3] (only 1 possible value of y can be seen as plotted on the gray]

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Which ordered pair is a solution of the equation? y-3=5(x-2) A.) (2,3) B.) (3,2) C.) Both D.) Neither

White raven [17]

Answer:

A is the only solution.

Step-by-step explanation:

A simple way to solve it is to plug in the x and y values

For A, we plug in 2 for x and 3 for y

3-3=5(2-2)

0=5(0)

0=0

Ordered pair A is a solution

For B, plug in 3 for x and 2 for y

2-3=5(3-2)

-1=5(1)

-1 does not equal 5

Therefore only A is a solution

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3 years ago

Given f(x)=x-7/3 solve for f^-1(4)

GrogVix [38]

I hope this hepls you

f⁻¹(x)=3x+7

f⁻¹(4)=3.4+7=19

8 0

3 years ago

Given p (x) = 5x - 6 what is the value of p ( 2/5)<br><br>Help me please quick! please

cluponka [151]

Answer:

p(2/5)=-4

Step-by-step explanation:

Plug in 2/5 for x

p(2/5)=5(2/5)-6

Combine like terms

p(2/5)=2-6

p(2/5)=-4

8 0

3 years ago

What is the 5th term in the sequence below? 255, 270, 285, 300,

lesya [120]

Answer:

315

Step-by-step explanation:

each one adds 15.

300 + 15 = 315

8 0

3 years ago

In a jury trial, suppose the probability the defendant is convicted, given guilt, is 0.95, and the probability the defendant is

Artyom0805 [142]

Answer:

The probability of the defendant is innocent given the defendant is convicted is P=0.006.

Step-by-step explanation:

Being:

G: guilty, I:innocent, C: convicted, A: acquitted.

We need to calculate P(I|C).

Being innocent, given convicted, is equal to the probability of being innocent and convicted divided by the probability of being convicted (innocent or guilty)

$P(I|C)=\frac{P(I\&C)}{P(C)}$

The probability of being innocent and convicted is

$P(I\&C)=P(C|I)*P(I)=0.05*0.1=0.005$

The probability of being convicted is equal to the sum of P(I&C) and P(G&C)

$P(C)=P(I\&C)+P(I\&C)=P(C|I)*P(I)+P(C|G)*P(G)\\\\P(C)=0.005+0.95*0.90=0.005+0.855=0.86$

Then,

$P(I|C)=\frac{P(I\&C)}{P(C)}=\frac{0.005}{0.86}= 0.006$

6 0

3 years ago