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kumpel [21]
3 years ago
10

A fruit fly experiment starts with 600 flies. If the number of flies after x days is given by the function P(x)=600e^0.3x, how m

any days will it be until there are 1000 flies?
(20 points)

Explain Your Answer!
Mathematics
1 answer:
slega [8]3 years ago
6 0
Since ln(x) is the inverse of e^x and we want to find out when P(x)=1000, we will substitute P(x) by 1000 and then solve for x days.

1600e^0.3x = 1000

Divide 600 for both sides you will get:

5/3 = e^0.3x

Multiply ( ln ) for both sides and then divide by 0.3.

(ln 5/3)/(0.3) = x

x = 1.7

So there will be 1000 flies in approximately 1.7 days
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The value of f(a)=4-2a+6a^{2}, f(a+h) is 6a^{2} +6h^{2} -2a-2h+12ah , [f(a+h)-f(a)]/h is 6h+12a-2 in the function f(x)=4-2x+6x^{2}.

Given a function f(x)=4-2x+6x^{2}.

We are told to find out the value of f(a), f(a+h) and [f(a+h)-f(a)]/hwhere h≠0.

Function is like a relationship between two or more variables expressed in equal to form.The value which we entered in the function is known as domain and the value which we get after entering the values is known as codomain or range.

f(a)=4-2a+6a^{2} (By just putting x=a).

f(a+h)==4-2(a+h)+6(a+h)^{2}

=4-2a-2h+6(a^{2} +h^{2} +2ah)

=4-2a-2h+6a^{2} +6h^{2} +12ah

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[f(a+h)-f(a)]/h=[6a^{2} +6h^{2}-2a-2h+12ah-(4-2a+6a^{2} )]/h

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=(6h^{2} -2h+12ah)/h

=6h+12a-2.

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Learn more about function at brainly.com/question/10439235

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