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sladkih [1.3K]
3 years ago
13

A video game rental charges of $50 membership fee and $8 for each game rented right a linear equation in slope intercept form to

model this situation
Mathematics
1 answer:
stiks02 [169]3 years ago
4 0

Answer:

y= 50+8x

Step-by-step explanation:

Given data

Charges

Membership= $50

Each game= $8

Let the number of games be x and the total charges be y

so that the expression for the total charges be

y= 50+8x

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the length of rectangle exceeds its breadth by 4 cm if the length and breadth is increased by 3 cm the area of the new rectangle
gizmo_the_mogwai [7]

Answer:

The length and breadth are 14 cm and 10 cm

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3 years ago
As a river guide on the gauja river, antra earned $55 per passenger and a $25 tip. if she earned $410 altogether, how many passe
Ket [755]

410 - 25 = 386

385 ÷ 55 = 7 passengers


5 0
3 years ago
Read 2 more answers
What is the greatest common factor of 14 56 63?
olga55 [171]
14: 1 × 14
      2 × 7

56: 1 × 56
      2 × 28
      4 × 14
      7 × 8

63: 1 × 63
      3 × 21
      7 × 9
GCF(14, 56, 63) = 7
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3 years ago
The cost of a service call to fix a washing machine can be expressed by the linear function , where y represents the total cost
mixas84 [53]
It would be A bud hope this helps
7 0
4 years ago
a slitter assembly contains 48 blades five blades are selected at random and evaluated each day for sharpness if any dull blade
son4ous [18]

Answer:

P(at least 1 dull blade)=0.7068

Step-by-step explanation:

I hope this helps.

This is what it's called dependent event probability, with the added condition that at least 1 out of 5 blades picked is dull, because from your selection of 5, you only need one defective to decide on replacing all.

So if you look at this from another perspective, you have only one event that makes it so you don't change the blades: that 5 out 5 blades picked are sharp. You also know that the probability of changing the blades plus the probability of not changing them is equal to 100%, because that involves all the events possible.

P(at least 1 dull blade out of 5)+Probability(no dull blades out of 5)=1

P(at least 1 dull blade)=1-P(no dull blades)

But the event of picking one blade is dependent of the previous picking, meaning there is no chance of picking the same blade twice.

So you have 38/48 on getting a sharp one on your first pick, then 37/47 (since you remove 1 sharp from the possibilities, and 1 from the whole lot), and so on.

Also since are consecutive events, you need to multiply the events.

The probability that the assembly is replaced the first day is:

P(at least 1 dull blade)=1-P(no dull blades)

P(at least 1 dull blade)=1-(\frac{38}{48}* \frac{37}{47} *\frac{36}{46}*\frac{35}{45}*\frac{34}{44})

P(at least 1 dull blade)=1-0.2931

P(at least 1 dull blade)=0.7068

5 0
3 years ago
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