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slavikrds [6]
3 years ago
13

Are all spheres similar?

Mathematics
2 answers:
shtirl [24]3 years ago
7 0

Answer:

Yes, all spheres are similar to each other.

Step-by-step explanation:

We have to tell all the spheres are similar.

As the spheres has no other configuration except for being perfectly round three-dimensionally. Actually  a sphere's only important measurement is its radius since diameter, circumference, and everything else depends on the radius anyway. All are of similar shapes as only radius differs.

Hence, all spheres are similar to each other.

AnnZ [28]3 years ago
4 0
All spheres are similar because there are no other configuration of spheres except for being perfectly round three-dimensionally. Similar shapes are shapes where angles are similar as well as the sides which can just be determined through ratio and proportion
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Deshaun is fertilizing his garden. The garden is in the shape of a rectangle. Its length is 14 feet and its width is 11 feet. Su
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Answer:

length x width = area

14 x 11 = 154

154 / 22 = 7 fertilizer needed

Hope this helps

Step-by-step explanation:

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Please help fast!!!! Find the seventh term of the geometric sequence if a1=7 and r=3
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Answer:

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Step-by-step explanation:

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You roll two fair dice, a green one and a red one. (a) What is the probability of getting a sum of 7? (Enter your answer as a fr
Lera25 [3.4K]

Answer:

a) 0.167  b)0.056  c)0.023

Step-by-step explanation:

We are given the following information:

Sample space = {(1,1),(1,2),(1,3),(1,4),(1,5),(1,6)

                            (2,1),(2,2),(2,3),(2,4),(2,5),(2,6)

                            (3,1),(3,2),(3,3),(3,4),(3,5),(3,6)

                            (4,1),(4,2),(4,3),(4,4),(4,5),(4,6)

                            (5,1),(5,2),(5,3),(5,4),(5,5),(5,6)

                            (6,1),(6,2),(6,3),(6,4),(6,5),(6,6)}

Total number of outcomes = 36

Formula:

\text{Probability} = \displaystyle\frac{\text{Number of favourable outcomes}}{\text{Total number of outcomes}}

a) P(sum is 7)

Sum 7 possible outcomes = {(1,6), (2,5), (3,4), (4,3), (5,2), (6,1)}

= P = \displaystyle\frac{6}{36} = \displaystyle\frac{1}{6} = 0.167

b) P(sum is 11)

Sum 11 possible outcomes = {(5,6), (6,5)}

= P = \displaystyle\frac{2}{36} = \displaystyle\frac{1}{18} = 0.056

c) P( sum is 7 or sum is 11)

= P(\text{sum is 7}) + P(\text{sum is 11}) - (P(\text{sum is 7}\cap \text{sum is 11})) \\= \displaystyle\frac{6}{36} + \displaystyle\frac{2}{36} + 0\\\\= \displaystyle\frac{8}{36} = \displaystyle\frac{2}{9} = 0.223

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Nana76 [90]

Answer:

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Step-by-step explanation:

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Answer:

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D=4H+35

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