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Mazyrski [523]
3 years ago
14

A student has selected 8 books that she likes, but she has money only for 3 books. how many possible selections does she have?

Mathematics
2 answers:
ladessa [460]3 years ago
5 0
Since the order of the books chosen doesn't matter, we use the combination formula to find the number of possible selections. Recall that a combination of k items from a set of n items is given by   nCk= \frac{n!}{k!(n-k)!}. 

In this problem, n = 8 and k = 3. So the number of possible selections is 
8C3= \frac{8!}{3!(8-3)!}=56. Thus the answer is 56.
Brums [2.3K]3 years ago
5 0
<span>The student has 6,720 selections to choose from. Because order doesn’t matter, the problem is a combinations function. It is solved by dividing the factorial of 8 by the factorial of 3. So (8*7*6*5*4*3*2*1)/(3*2*1)</span>
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