Answer:
(2,1)
Step by step explanation:
Please find the attachment.
We have been given that line 
is horizontal and passes through point (1,1). Line 
is vertical and passes through point (2,2). We are asked to find point of intersection of line and line .
Line is a horizontal line so y-coordinate will be 1 for any value of x. Line is a vertical line, so x-coordinate will be 2 for any value of y.
Therefore, intersection point of both lines will include x-coordinate of line and y-coordinate of line that is (2,1).
The answer is : D. 2*2*2*2*2*5
Answer:
-24.8 m/s
Step-by-step explanation:
Given:
y₀ = 60 m
y = 40 m
v₀ = 15 m/s
a = -9.8 m/s²
Find: v
There are three constant acceleration equations we can use:
y = y₀ + v₀ t + ½ at²
v = at + v₀
v² = v₀² + 2a(y − y₀)
We aren't given the time, so we need to use the third equation, which is independent of time:
v² = v₀² + 2a(y − y₀)
Plug in the values:
v² = (15 m/s)² + 2(-9.8 m/s²) (40 m − 60 m)
v² = 617 m²/s²
v ≈ ±24.8 m/s
Since the coin is on the way down, the velocity is negative. So v = -24.8 m/s.
Answer:
The point on the y-axis is (0,-3) and the point on the x-axis is (6,0)
Step-by-step explanation:
Start by plotting -3 on the y-axis
Then move up 1 and over 2 from there
Answer:
B
Step-by-step explanation:
