32 divided by (3+7) = 3.2
3.2x3= 9.6
3.2x7= 22.4
Therefore 9.6:22.4
D=event that chip selected is defective
d=event that chip selected is NOT defective
Four possible scenarios for the first two selections:
P(DDD)=15/100*14/99*13/98=13/4620
P(DdD)=15/100*85/99*14/98=17/924
P(dDD)=85/100*15/99*14/99=17/924
P(ddD)=85/100*84/99*15/98=17/154
Probability of third selection being defective is the sum of all cases,
P(XXD)=P(DDD)+P(DdD)+P(dDD)+P(ddD)
=3/20
Answer:
Step-by-step explanation:
Plug in the 6 to the equations. Since B is the midpoint of AC, then both should be equal once plugged in [and solved].
You can solve this using proportion.
5 = 4
7 = ?
7(4)/5= 5.6
7 cakes cost £5.6
Missing question: How many executives should be surveyed?
Solution:
Mean = 13 hours
SD = 3 hours
Confidence level = 95%
Mean viewing time within a quarter of an hour = 0.25 = 1.96*3/sqrt (N)
Where N = Sample population
N = {(1.96*3)/0.25}^2 = 553.19 ≈ 554
Therefore, 554 executives should be surveyed to yield such results.
