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ehidna [41]
3 years ago
6

Find the length of AB? Round to the nearest tenth

Mathematics
1 answer:
aev [14]3 years ago
5 0

Answer:

AB ≈ 8.5

Step-by-step explanation:

a^{2} + b^{2} = c^{2} \\\\c = \sqrt{a^{2} + b^{2} } \\\\c = \sqrt{6^{2} + 6^{2} } \\\\c = \sqrt{36 + 36 } \\\\c = \sqrt{72 } \\\\c = 8.48528137424 \\

c ≈ 8.5

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∠ACE is formed by two secants intersecting outside of a circle. If minor arc BD = 25°, minor arc AB = 115°, and minor arc DE = 1
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Step-by-step explanation:

Consider the below figure attached with this question.

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