Answer:
Value of x is 8
Step-by-step explanation:
Given:
So, Value of x is 8
Answer:
Option B
Step-by-step explanation:
HHH → All heads
HHT → Two heads + one tail
HTH → Two heads + one tail
HTT → Two tails + one head
THH → One tail + two heads
THT → Two tails + one head
TTH → Two tails + one head
TTT → All tails
Therefore, At least two tails means → Sample space outcome with two tails Or all tails
Therefore, from the given options HTT is having two tails.
Option B is the correct option.
Answer: 2 4/15 months
Step-by-step explanation:
From the question, we are informed that a wagon train traveled from Missouri to Wyoming in 1 2/3 months and from Wyoming to Utah in 3/5 month.
The number of months that it will take the wagon train to travel from Missouri to Utah will be:
= 1 2/3 + 3/5
The common lowest multiple is 15
= 1 10/15 + 9/15
= 1 19/15
= 1 + 1 4/15
= 2 4/15 months
It will take they train 2 4/15 months to travel from Missouri to Utah.
Answer:
The solution is 12. The equation is (115 - 19) ÷ 8.
Step-by-step explanation:
We can solve this problem by using division.
First, let's take away 19.
115 - 19 = 96
Now let's divide 96 by 8.
96 ÷ 8 = 12.
And we have 12, our answer.
Answer:
The running time is quadratic (O(n²) )
Step-by-step explanation:
For the set up, we have a constant running time of C. The, a log-linearsorting is called, thus, its execution time, denoted by T(n), is O(n*log(n)). Then, we call n times a linear iteration, with a running time of an+b, for certain constants a and b, thus, the running time of the algorithm is
C + T(n) + n*(a*n+b) = an²+bn + T + C
Since T(n) is O(n*log(n)) and n² is asymptotically bigger than n*log(n), then the running time of the algorith is quadratic, therefore, it is O(n²).
