Answer:
The cost of 1 pound meat is $ 4.5 And cost of 1 pound of cheese is $ 2.5.
Step-by-step explanation:
Let the cost of 1 pound of meat be x
Let the cost of 1 pound of cheese be y
Cost of 4 pounds of meat = 4x
Cost of 5 pounds of cheese = 5y
Since we are given that one customer purchases 4 pounds of meat and 5 pounds of cheese for a total of $30.50.
So, equation becomes :
Cost of 11 pounds of meat = 11x
Cost of 14 pounds of cheese = 14y
Since we are given that a sandwich shop owner comes in and purchases 11 pounds of meat and 14 pounds of cheese for $84.50.
So, equation becomes :
Thus the system of equations are :
-1 (Red line)
-2 (Black line)
Solving these equations graphically we get the solution
x = $4.5
y = $2.5
Hence The cost of 1 pound meat is $ 4.5 And cost of 1 pound of cheese is $ 2.5.
Mathematically, 10 times.
Realistically, you can't tell.
Just substitute 32 for p in the equation
3(32)+2=m
96+2=m
M=98
<span>Answer:
K = (1/2) mv² + (1/2) Iω², where m is the ball mass, I is the ball's moment of inertia (2/5)mr², and ω is the angular velocity of the ball. Because the ball rolls without slipping, it is easy to see that v=ωr, or r=v/ω. Then,
K = (1/2)mv² + (1/2)(2/5)mr²ω²
= (1/2)mv² + (1/5)mv²
= (7/10)mv²
Setting potential at the top equal to kinetic at the bottom,
mgh=(7/10)mv²
v=âš{(10/7)(gh)}
= [(10/7)(9.8)(0.51)]^(1/2) = 2.672m/s</span>
