Answer:
Kennan will be from home approximately an hour and 48 minutes.
Step-by-step explanation:
We must know that total time (
) that Keenan will be from home is the sum of run (
), hang out (
) and walk times (
), measured in hours:

If Keenan runs and walks at constant speed, then equation above can be expanded:

Where:
,
- Run and walk distances, measured in miles.
,
- Run and walk speeds, measured in miles per hour.
Given that
,
,
and
, the total time is:

(
)
Kennan will be from home approximately an hour and 48 minutes.