For part (a), first consider the simple case where we roll two dice.What is the probability that the second roll is greater than the first? Assuming a six-sided dice, the total number of outcomes $(i,j)$ is $6^2$.
Because the number has to have no greater divisors other than one or itself
Answer:
y = (2x + 3)(2x + 3) = (2x + 3)²
Step-by-step explanation:
We are given a quadratic function and we have to write it in factored form.
y = 9 + 12x + 4x²
y = 4x² + 12x + 9
We can break the mid-term in such a way that when they are multiplied, the factors give a product of 36x² and when added, they give a result of 12x, as show below:
y = 4x² + 6x + 6x + 9
Taking 2x common from the first two variables and 3 from the second two
y = 2x(2x + 3) + 3(2x + 3)
Taking 2x+3 common
y = (2x + 3)(2x + 3) = (2x + 3)²
Answer: 60 cm
Step-by-step explanation:
multiply sides together.
J
Because 15 - 13 is 2 x (8 + 4 = 24 and divided by 6 is 4
