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d1i1m1o1n [39]
3 years ago
11

Can u please help me?

Mathematics
1 answer:
alukav5142 [94]3 years ago
4 0
Lori will need 5 basket and she will fill them equally by putting 7 peaches in each basket.
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15 is 30% of what number?
Kisachek [45]
0.5 times 100 = 50... 50 is your answer
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For the graphed function f(x) = −(5)x − 3 + 2, calculate the average rate of change from x = 3 to x = 4.
azamat

Answer:

-4 is the average rate of change from 3 to 4

Step-by-step explanation:

Average rate of change is defined as the fraction of change in f(x) value to change in x value.

Here we have x values as 3 and 4.

To find the average rate of change from x=3 to x=4

Average rate of change = change in f(x)/change in x

f(4) = -5^{4-3} +2 = -3\\f(3) = 1\\f(4)-f(3) = -3-1 =-4

Change in x = 4-3 =1

6 0
3 years ago
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Use the slope formula to find the slope of the line that passes through the points (6,3) and (9,8).
Anni [7]
Correct answer is 5/3
8 0
2 years ago
A length of 5 cm on a map represents a distance of 2km on the ground .What length on the map represents an actual distance of 80
kipiarov [429]

Answer:

which means easily we understand by SI UNIT

0.05m=2kM

800M=???, USE cris cros

Step-by-step explanation:

finally answer will be 0.000032

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2 years ago
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According to the South Dakota Department of Health, the number of hours of TV viewing per week is higher among adult women than
Murrr4er [49]

Answer:

a) P(x<40) = 0.90824

Therefore, the percent of the women watch TV less than 40 hours per week is 0.90824 × 100 = 90.8240%

b)P(x>25) = 1 - P(z = -0.78) = 0.7823

Therefore, percent of the men watch TV more than 25 hours per week?is 0.7823 × 100 = 78.230%

c)The number of hours that the one percent of WOMEN who watch the most TV per week watch is for 44.485hours

While, for the MEN, the number of hours that the one percent of men who watch the most TV per week watch is for 40.883 hours

Step-by-step explanation:

To solve this question, we would be using z score formula:

z = (x-μ)/σ,

where x is the raw score

μ is the population mean

σ is the population standard deviation.

a. What percent of the women watch TV less than 40 hours per week? (Round z-score computation to 2 decimal places and your final answer to 4 decimal places.)

z = (x-μ)/σ,

where x is the raw score = 40 hours

μ is the population mean = 34 hours

σ is the population standard deviation = 4.5

z = (40 - 34)/4.5

z = 1.33333

Approximately to 2 decimal places = z score = 1.33

Using the normal distribution z score table

Probabilty value from Z-Table:

P(z = 1.33) = P(x<40) = 0.90824

Therefore, the percent of the women watch TV less than 40 hours per week is 0.90824 × 100 = 90.8240%

b. What percent of the men watch TV more than 25 hours per week? (Round z-score computation to 2 decimal places and your final answer to 4 decimal places.)

z = (x-μ)/σ,

where x is the raw score = 25 hours

μ is the population mean = 29 hours

σ is the population standard deviation = 5.1

z = (25 - 29)/5.1

z = -0.78431

Approximately to 2 decimal places

z score = -0.78

Using the z score normal distribution table:

Probability value from Z-Table:

P(z = -0.78) = P(x<Z) = 0.2177

P(x>25) = 1 - P(z = -0.78) = 0.7823

Therefore, percent of the men watch TV more than 25 hours per week?is 0.7823 × 100 = 78.230%

c. How many hours of TV do the one percent of women who watch the most TV per week watch? Find the comparable value for the men. (Round your answers to 3 decimal places.)

First, we find what the z score is.

We were asked in the question to find how many hours 1% of the women watch TV the most.

We have to find the confidence interval

100 - 1% = 99%

The z score for the confidence interval of 99% or 0.99(in decimal form) = 2.33

z score = 2.33

Since we know the z score now, we proceed to find x = raw score.

z = (x-μ)/σ,

where x is the raw score = unknown

μ is the population mean = 34 hours

σ is the population standard deviation = 4.5

2.33= (x - 34)/4.5

Cross Multiply

2.33 × 4.5 = x - 34

10.485 = x - 34

x = 10.485 + 34

x = 44.485 hours.

Therefore, the number of hours that the one percent of women who watch the most TV per week watch is for 44.485hours

In the question, we were also asked to find the comparable value for men.

Hence, for one percent of the men.

We determine what the z score is.

We were asked in the question to find how many hours 1% of the men watch TV the most.

We have to find the confidence interval

100 - 1% = 99%

The z score for the confidence interval of 99% or 0.99(in decimal form) = 2.33

We already have our z score as 2.33

z = (x-μ)/σ,

where x is the raw score = unknown

μ is the population mean = 29 hours

σ is the population standard deviation = 5.1

2.33= (x - 29)/5.1

Cross Multiply

2.33 × 5.1 = x - 29

11.883 = x - 29

x = 11.883 + 29

x = 40.883 hours.

Therefore, the number of hours that the one percent of men who watch the most TV per week watch is for 40.883 hours

8 0
3 years ago
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