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Jet001 [13]
3 years ago
11

Dave has 15$ to spend on a book for 8$ and two birthday cards (c) for his friends. How much can he spend on each card if he buys

the same card for each friend
Mathematics
2 answers:
masha68 [24]3 years ago
4 0
Three dollars and fifty cents for each card.
NNADVOKAT [17]3 years ago
4 0
$3.50


$8+$3.50+$3.50=$15
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This will clear up the last questions i asked
kow [346]

Answer:

Step-by-step explanation:

105 (11/12)

6 0
2 years ago
Read 2 more answers
Louise wants to visit El Paso San Diego Columbus Los Angeles Jacksonville San Antonio Austin and Chicago. If she decides to visi
MakcuM [25]
There are eight cities on the list.

The number of groups of 2 is (8·7)/2 = 28
The number of groups of 3 is (8·7·6)/(3!) = 56
The number of groups of 4 is (8·7·6·5)/(4!) = 70
The number of groups of 5 is (8·7·6·5·4)/(5!) = 56
The number of groups of 6 is (8·7·6·5·4·3)/(6!) = 28
The number of groups of 7 is (8·7·6·5·4·3·2)/(7!) = 8

So there are (28+56+70+56+28+8) = 246 ways to visit "some" of them.

There's only one way to visit "all" of them, and
there's only one way to visit "none" of them.

So, all together, Louise has 248 travel options.
If she decides to visit Chicago, I will show her a good time. 
8 0
3 years ago
A. n=55<br>b. n=25<br>c. n=5<br>d. n=3025​
Mnenie [13.5K]

Answer:

A

Step-by-step explanation:

Assuming the triangle is right, use Pythagoras' identity to find N

The square on the hypotenuse is equat to the sum of the squares on the other 2 sides.

Here the hypotenuse = 73, thus

N² + 48² = 73², that is

N² + 2304 = 5329 ( subtract 2304 from both sides )

N² = 3025 ( take the square root of both sides )

N = \sqrt{3025} = 55 → A

5 0
3 years ago
How many zeros are in the product (6×5)×10
ohaa [14]
There are 2 zeros in the product because 6•5=30•10=300 so there are 2 zeros
5 0
3 years ago
If the x-value repeats and the y does not, is it a function?
kogti [31]

Answer:

If X repeats and y does not it is not an example of a function. But if the y repeats and has two different x values that can be known as a function.

For an example ( 1 , 3) and (1, 4) thats not an example of a function because the x value is repeating but if its ( 1, 4) and (2,4) a thats

a function because no x value is repeating the x value is known as an independent value. Does that make sense?

"This relation is definitely a function because every x-value is unique and is associated with only one value of y. So for a quick summary, if you see any duplicates or repetitions in the x-values, the relation is not a function."

7 0
3 years ago
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