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musickatia [10]
3 years ago
5

la1" title="\sqrt{4x+1}-5=0\\\\\\\\\sqrt{5x-1}+3=x\\" alt="\sqrt{4x+1}-5=0\\\\\\\\\sqrt{5x-1}+3=x\\" align="absmiddle" class="latex-formula">
Can someone explain how to do these problems. I am struggling in this area and have no clue on what I am doing.
Mathematics
1 answer:
adoni [48]3 years ago
8 0

Answer:

what topic is this please

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Round 4.908 to the hundredths place.
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3 years ago
A car is driving away from a crosswalk. The formula d = t2 + 2t expresses the car's distance from the crosswalk in feet, d, in t
alukav5142 [94]

Answer:

8 feet per second.

Step-by-step explanation:

We have been given that a car is driving away from a crosswalk. The formula d=t^2+2t expresses the car's distance from the crosswalk in feet, d, in terms of the number of seconds, t, since the car started moving.

We will use average change formula to solve our given problem.

\text{Average change}=\frac{f(b)-f(a)}{b-a}

\text{Average change}=\frac{d(5)-d(1)}{5-1}

\text{Average change}=\frac{(5)^2+2(5)-((1)^2+2(1))}{4}

\text{Average change}=\frac{25+10-(1+2)}{4}

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Therefore, the the car's average speed over the given interval of time would be 8 feet per second.

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