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3 years ago

Given the sequence 12, 9, 6, 3,........ where x = 0, 1, 2......,

Mathematics

1 answer:

Nitella [24]3 years ago

4 0

Answer:

f(x) = -3x + 12

Step-by-step explanation:

The chart could be represented like this:

x y

0 12

1 9

2 6

3 3

Suppose that f(x) = y

And substitute x values.

y = -3x + 12

"x = 0"

y = -3(0) + 12

y = 0 + 12

y = 12

"x = 3"

y = -3(3) + 12

y = -9 + 12

y = 3

From the results, it corresponds to the function.

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QUICK ANSWER THIS!!!<br> j/-2+7=−12

VMariaS [17]

Answer:

Step-by-step explanation:

j/-2=-19

j=38

5 0

3 years ago

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If the demand function for a commodity is given by the equation

Margarita [4]

Answer:

Equilibrium quantity = 26.92

Equilibrium price is $31.13

Step-by-step explanation:

Given :Demand function : $p^2 + 16q = 1400$

Supply function : $700 -p^2 + 10q = 0$

To Find : find the equilibrium quantity and equilibrium price.

Solution:

Demand function : $p^2 + 16q = 1400$ --A

Supply function : $p^2-10q=700$ ---B

Now to find the equilibrium quantity and equilibrium price.

Solve A and B

Subtract B from A

$p^2-10q -p^2-16q=700-1400$

$-26q=-700$

$26q=700$

$q=\frac{700}{26}$

$q=26.92$

So, equilibrium quantity = 26.92

Substitute the value of q in A

$p^2 + 16(26.92) = 1400$

$p^2 + 430.72 = 1400$

$p^2 = 1400- 430.72$

$p^2 = 969.28$

$p = \sqrt{969.28}$

$p = 31.13$

So, equilibrium price is $31.13

7 0

3 years ago

Select the correct answer from each drop-down menu.

lesantik [10]

Answer: The sample mean is 14.98

The second one is NOT standard deviation

Step-by-step explanation: Sorry thats all i got but good luck!

7 0

2 years ago

How do you subtract 1 integer by another

nikdorinn [45]

Use absolute value. If both signs are negative you will get a negative number. if both are positive you get positive. if the signs are different, subtract the smaller absolute value from the larger absolute value.

8 0

3 years ago

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Given the circle with the equation (x + 1)2 + y2 = 36, determine the location of each point with respect to the graph of the cir

kati45 [8]

$\bf \textit{equation of a circle}\\\\ 
(x- h)^2+(y- k)^2= r^2
\qquad 
center~~(\stackrel{}{ h},\stackrel{}{ k})\qquad \qquad 
radius=\stackrel{}{ r}\\\\
-------------------------------\\\\
(x+1)^2+y^2=36\implies [x-(\stackrel{h}{-1})]^2+[y-\stackrel{k}{0}]^2=\stackrel{r}{6^2}~~~~
\begin{cases}
\stackrel{center}{(-1,0)}\\
\stackrel{radius}{6}
\end{cases}$

so, that's the equation of the circle, and that's its center, any point "ON" the circle, namely on its circumference, will have a distance to the center of 6 units, since that's the radius.

$\bf ~~~~~~~~~~~~\textit{distance between 2 points}
\\\\
(\stackrel{x_1}{-1}~,~\stackrel{y_1}{0})\qquad 
A(\stackrel{x_2}{-1}~,~\stackrel{y_2}{1})\qquad \qquad 
% distance value
d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}
\\\\\\
\stackrel{distance}{d}=\sqrt{[-1-(-1)]^2+(1-0)^2}\implies d=\sqrt{(-1+1)^2+1^2}
\\\\\\
d=\sqrt{0+1}\implies d=1$

well, the distance from the center to A is 1, namely is "inside the circle".

$\bf ~~~~~~~~~~~~\textit{distance between 2 points}
\\\\
(\stackrel{x_1}{-1}~,~\stackrel{y_1}{0})\qquad 
B(\stackrel{x_2}{-1}~,~\stackrel{y_2}{6})\\\\\\
\stackrel{distance}{d}=\sqrt{[-1-(-1)]^2+(6-0)^2}\implies d=\sqrt{(-1+1)^2+6^2}
\\\\\\
d=\sqrt{0+36}\implies d=6$

notice, the distance to B is exactly 6, and you know what that means.

$\bf ~~~~~~~~~~~~\textit{distance between 2 points}
\\\\
(\stackrel{x_1}{-1}~,~\stackrel{y_1}{0})\qquad 
C(\stackrel{x_2}{4}~,~\stackrel{y_2}{-8})
\\\\\\
\stackrel{distance}{d}=\sqrt{[4-(-1)]^2+[-8-0]^2}\implies d=\sqrt{(4+1)^2+(-8)^2}
\\\\\\
d=\sqrt{25+64}\implies d=\sqrt{89}\implies d\approx 9.43398$

notice, C is farther than the radius 6, meaning is outside the circle, hiking about on the plane.

3 0

3 years ago

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