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Sphinxa [80]
3 years ago
7

Given the sequence 12, 9, 6, 3,........ where x = 0, 1, 2......,

Mathematics
1 answer:
Nitella [24]3 years ago
4 0

Answer:

f(x) = -3x + 12

Step-by-step explanation:

The chart could be represented like this:

x             y

0            12

1             9

2            6

3            3

Suppose that f(x) = y

And substitute x values.

y = -3x + 12

"x = 0"

y = -3(0) + 12

y = 0 + 12

y = 12

"x = 3"

y = -3(3) + 12

y = -9 + 12

y = 3

From the results, it corresponds to the function.

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QUICK ANSWER THIS!!!<br> j/-2+7=−12
VMariaS [17]

Answer:

38

Step-by-step explanation:

j/-2=-19

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3 years ago
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If the demand function for a commodity is given by the equation
Margarita [4]

Answer:

Equilibrium quantity = 26.92

Equilibrium price is $31.13

Step-by-step explanation:

Given :Demand function : p^2 + 16q = 1400

           Supply function : 700 -p^2 + 10q = 0

To Find : find the equilibrium quantity and equilibrium price.

Solution:

Demand function : p^2 + 16q = 1400  --A

Supply function : p^2-10q=700 ---B

Now to find the equilibrium quantity and equilibrium price.

Solve A and B

Subtract B from A

p^2-10q -p^2-16q=700-1400

-26q=-700

26q=700

q=\frac{700}{26}

q=26.92

So, equilibrium quantity = 26.92

Substitute the value of q in A

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p^2 = 1400- 430.72

p^2 = 969.28

p = \sqrt{969.28}

p = 31.13

So, equilibrium price is $31.13

7 0
3 years ago
Select the correct answer from each drop-down menu.
lesantik [10]

Answer: The sample mean is 14.98

The second one is NOT standard deviation

Step-by-step explanation: Sorry thats all i got but good luck!

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How do you subtract 1 integer by another
nikdorinn [45]
Use absolute value. If both signs are negative you will get a negative number. if both are positive you get positive. if the signs are different, subtract the smaller absolute value from the larger absolute value.
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so, that's the equation of the circle, and that's its center, any point "ON" the circle, namely on its circumference, will have a distance to the center of 6 units, since that's the radius.

\bf ~~~~~~~~~~~~\textit{distance between 2 points}&#10;\\\\&#10;(\stackrel{x_1}{-1}~,~\stackrel{y_1}{0})\qquad &#10;A(\stackrel{x_2}{-1}~,~\stackrel{y_2}{1})\qquad \qquad &#10;%  distance value&#10;d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}&#10;\\\\\\&#10;\stackrel{distance}{d}=\sqrt{[-1-(-1)]^2+(1-0)^2}\implies d=\sqrt{(-1+1)^2+1^2}&#10;\\\\\\&#10;d=\sqrt{0+1}\implies d=1

well, the distance from the center to A is 1, namely is "inside the circle".

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notice, the distance to B is exactly 6, and you know what that means.

\bf ~~~~~~~~~~~~\textit{distance between 2 points}&#10;\\\\&#10;(\stackrel{x_1}{-1}~,~\stackrel{y_1}{0})\qquad &#10;C(\stackrel{x_2}{4}~,~\stackrel{y_2}{-8})&#10;\\\\\\&#10;\stackrel{distance}{d}=\sqrt{[4-(-1)]^2+[-8-0]^2}\implies d=\sqrt{(4+1)^2+(-8)^2}&#10;\\\\\\&#10;d=\sqrt{25+64}\implies d=\sqrt{89}\implies d\approx 9.43398

notice, C is farther than the radius 6, meaning is outside the circle, hiking about on the plane.
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