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3 years ago

Factor completely. 3w2+18w+27

Mathematics

2 answers:

Rasek [7]3 years ago

7 0

3w2+18w+27
= 3(w2+6w+9)
= 3 (w + 3)^2 (using this formula: (a + b)^2 = a^2 + 2ab + b^2)

zimovet [89]3 years ago

3 0

3(w+3)^2 would be your answer.

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10 ft

Gnom [1K]

Answer:

105.12 feets

Step-by-step explanation:

From the figure x we can identify a rectangle and a semicircle :

Area of rectangle = Length * width

Area = 8 * 10 = 80 feet²

The Area of a semicircle = 1/2πr²

Radius, r = 8 /2 = 4 feets

A = 1/2 * 3.14 * 4²

A = 3.14 * 8

A = 25.12 feet²

Area of figure = 80 + 25.12 = 105.12 feets

4 0

3 years ago

2. In a given population of two-earner male-female couples, male earnings have a mean of $40,000 per year and a standard deviati

Kobotan [32]

Answer: $85,000

Step-by-step explanation:

Given : In a given population of two-earner male-female couples, male earnings have a mean of $40,000 per year and a standard deviation of $12,000.

$\mu_M=40,000\ \ ;\sigma_M=12,000$

Female earnings have a mean of $45,000 per year and a standard deviation of $18,000.

$\mu_F=45,000\ \ ;\sigma_F=18,000$

If C denote the combined earnings for a randomly selected couple.

Then, the mean of C will be :-

$\mu_c=\mu_M+\mu_F\\\\=40,000+45,000=85,000$

Hence, the mean of C = $85,000

8 0

3 years ago

Brad can type 1260 words in 1/2 hour. What is Brad’s average typing rate in words per minute?

Ilia_Sergeevich [38]

Brad average typing rate in words per minute is 21

1260 divided by 60 = 21

(In case you meant 30 minutes)

1260 divided by 30 = 42

5 0

3 years ago

The braking distance, in feet of a car a Travling at v miles per hour is given.

irakobra [83]

The braking distance is the distance the car travels before coming to a stop after the brakes are applied

a. The braking distances are as follows;

The braking distance at 25 mph, is approximately 63.7 ft.

The braking distance at 55 mph, is approximately 298.35 ft.

The braking distance at 85 mph, is approximately 708.92 ft.

b. If the car takes 450 feet to brake, it was traveling with a speed of 98.211 ft./s

Reason:

The given function for the braking distance is D = 2.6 + v²/22

a. The braking distance if the car is going 25 mph is therefore;

25 mph = 36.66339 ft./s

$D = 2.6 + \dfrac{36.66339^2}{22} = 63.7 \ ft.$

At 25 mph, the braking distance is approximately 63.7 ft.

At 55 mph, the braking distance is given as follows;

55 mph = 80.65945 ft.s

$D = 2.6 + \dfrac{80.65945^2}{22} \approx 298.35 \ ft.$

At 55 mph, the braking distance is approximately 298.35 ft.

At 85 mph, the braking distance is given as follows;

85 mph = 124.6555 ft.s

$D = 2.6 + \dfrac{124.6555^2}{22} \approx 708.92 \ ft.$

At 85 mph, the braking distance is approximately 708.92 ft.

b. The speed of the car when the braking distance is 450 feet is given as follows;

$450 = 2.6 + \dfrac{v^2}{22}$

v² = (450 - 2.6) × 22 = 9842.8

v = √(9842.2) ≈ 98.211 ft./s

The car was moving at v ≈ 98.211 ft./s

Learn more here:

brainly.com/question/18591940

8 0

2 years ago

Which of the choices shown are the lengths of the sides of a right triangle

Triss [41]

D because , 10+ 24 greater than 26
You need take the first and the second number add together must be greater the last one.
10,24,26
10+24 = 34
34>26

5 0

3 years ago

Read 2 more answers