Answer:
slope of EF=
∠QSR=45°,
∠PTQ=90°
if RT=24
then SQ=48
square is always a rectangle
∠SUT=21°
Step-by-step explanation:
two line are perpendicular to each other if product of their slope equal to -1
=-1
slope of HE=
=-
slope of EF=
slope of EF=-1
=
slope of EF=
answer
∠QSR=45°,
∠PTQ=90°
if RT=24
then SQ=48
square is always a rectangle
given ∠SUT=3x+6
∠RUS=5x-4
∠SUT=∠RUS
3x+6=5x-4
x=5
∠SUT=3x+6=15+6=21°
∠SUT=21°
where is the question to this
I dont know if this could help you but if you can please try to answer those two that I didn't complete so you could have an idea on what there relationships are and things like that.
Answer: The area is 
Step-by-step explanation:
The cross section AFGD is a rectangle. Then, its area can be calculated with this formula:

Where:
"A" is the area of the rectangle.
"l" is the lenght of the rectangle.
"w" is the width of the rectangle.
Then, from the figure, you can identify that the dimensions of the rectangle AFGD are:

Therefore, you can substitute these values into the formula
to find the area of the cross section AFGD. Then, you get:

Step-by-step explanation:
=
38.64=9.2h/2
=
38.64=4.6h
=
h = 38.64/4.6
h = 8.4
thats it