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Debora [2.8K]
3 years ago
5

Find the length and width of a rectangle whose perimeter is 26 feet and whose area is 42 square feet

Mathematics
1 answer:
likoan [24]3 years ago
8 0

Answer: length = 7 feet's

Width = 6 feets

Step-by-step explanation:

Perimeter of a rectangle is the distance round the rectangle.

Perimeter of rectangle is expressed as

2(length + width)

The perimeter of the given rectangle is 26 feet. Therefore

2(L + W) = 26

Dividing by 2,

L+W = 13

The area of a rectangle is expressed as length × width

The given area is 42 square feet. Therefore,

L×W = 42

Substituting L = 13 - W into LW = 42, it becomes

W(13-W) = 42

13W - W^2 = 42

W^2 -13W + 42 = 0

W^2 -7W - 6W + 42 = 0

W(W - 7) - 6(W - 7) = 0

(W-6)(w-7)=0

W-6 = 0 or W-7=0

W=6 or W = 7

L= 13-6 or L= 13-7

L= 7 or L = 6

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Find the area of the isosceles triangle. please help thanks
fiasKO [112]

Answer:

1080 m^2 Don't submit m^2 in your answer.

Step-by-step explanation:

Givens

The catch is to find h

To do that, use a^2 + b^2 = c^2

a b and c are in the same 1/2 triangle.

a = 48/2 = 24 m

b = h = ?

c = 51 meters

Solution

a^2 + b^2 = 51^2                      Substitute for b^2 = h^2

24^2 + h^2 = 51^2                   Expand 24^2 and 51^2

576 + h^2 = 2601                    Subtract 576 from both sides

h^2 = 2601 - 576

h^2 = 2025                              Take the square root of both sides

h = 45

Area

Area = 1/2 b * h

Area = 1/2 48 * 45

Area = 1080

Remark

Notice that to find h you only use 1/2 of 48 because that is the base of the right triangle.

To find the area, you need to use all of 48 because 48 is the full length of the base.

5 0
3 years ago
PLEASE HELP ITS ABOUT TO BE DUE
Jlenok [28]

Answer:

x=-1

Step-by-step explanation:

4(x-3(-2))=6(x-3(-2)) => 4(x+6)=6(x+6) => 4x+24=6x+26 => -2=2x => x=-1

6 0
3 years ago
What is the slope of a line perpendicular to the line whose equation is 3x+6y=-183x+6y=−18. Fully reduce your answer.
schepotkina [342]

Answer:

2

Step-by-step explanation:

The given equation of line is

3x+6y=-18

We need to find the slope of a line which is perpendicular to the given line.

The given equation can be rewritten as

3x+6y+18=0      ...(i)

If a line is defined as ax+bx+c=0, then the slope of the line is  

m=-\dfrac{a}{b}

In equation (i), a=3, b=6 and c=18. So, slope of the line is

m_1=-\dfrac{3}{6}=-\dfrac{1}{2}

Let m_2 be the slope of perpendicular line.

We know that product of two perpendicular line is -1.

m_1\cdot m_2=-1

(-\dfrac{1}{2})\cdot m_2=-1

Multiply both sides by -2.

m_2=2

Therefore, the slope of perpendicular line is 2.

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3 years ago
Plz help! I will make you the brainliest! Thanks!
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