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Jet001 [13]
3 years ago
6

A certain antihistamine is often prescribed for allergies. A typical dose for a 100​-pound person is 25 mg every six hours. Comp

lete parts​ (a) and​ (b) below. a. Following this​ dosage, how many 12.8 mg chewable tablets would be taken in a​ week? b. This antihistamine also comes in a liquid form with a concentration of 12.8 ​mg/9 mL. Following the prescribed​ dosage, how much liquid antihistamine should a 100​-pound person take in a​ week?
Mathematics
1 answer:
koban [17]3 years ago
3 0

Given that a certain antihistamine is often prescribed for allergies.

And typical dose for 100-pound person is 25 mg every 6 hours.

a) Let us calculate dose per 1 hour for 100-pound person= \frac{25}{6} mg/hr

Since 1 week means 7X24= 168 hours, dosage per 1 week = dosage per 168 hours

                                                                                 =168X\frac{25}{6} = 700mg

The number of 12.8 chew able tablets would be taken in a week= \frac{700}{12.8}=54.6875

Hence number of 12.8mg chew able tablets would be taken in a week is 55.

b) Now we can use earlier answer for this problem, since 12.8mg tablet is replaced with 9ml liquid, 55 bottles of 9ml liquid are to be taken in a week.

Hence amount of liquid histamine should a 100-pound person take in a week = 55X9

                                                                                                                                 =495ml

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Two tanks hold a total of 55 gallons of a toxic solvent. One tank holds 4 gallons more than twice the amount in the other. How m
Serhud [2]

Step-by-step explanation:

If x is the volume of the first tank, and y is the volume of the second tank, then:

x + y = 55

x = 2y + 4

Solve the system of equations using either substitution or elimination.  Using substitution:

2y + 4 + y = 55

3y + 4 = 55

3y = 51

y = 17

Solve for x using either equation.

x + 17 = 55

x = 38

The first tank holds 38 gallons, and the second tank holds 17 gallons.

8 0
3 years ago
Read 2 more answers
One urn contains one blue ball (labeled B1) and three red balls (labeled R1, R2, and R3). A second urn contains two red balls (R
marusya05 [52]

Answer:

(a) See attachment for tree diagram

(b) 24 possible outcomes

Step-by-step explanation:

Given

Urn\ 1 = \{B_1, R_1, R_2, R_3\}

Urn\ 2 = \{R_4, R_5, B_2, B_3\}

Solving (a): A possibility tree

If urn 1 is selected, the following selection exists:

B_1 \to [R_1, R_2, R_3]; R_1 \to [B_1, R_2, R_3]; R_2 \to [B_1, R_1, R_3]; R_3 \to [B_1, R_1, R_2]

If urn 2 is selected, the following selection exists:

B_2 \to [B_3, R_4, R_5]; B_3 \to [B_2, R_4, R_5]; R_4 \to [B_2, B_3, R_5]; R_5 \to [B_2, B_3, R_4]

<em>See attachment for possibility tree</em>

Solving (b): The total number of outcome

<u>For urn 1</u>

There are 4 balls in urn 1

n = \{B_1,R_1,R_2,R_3\}

Each of the balls has 3 subsets. i.e.

B_1 \to [R_1, R_2, R_3]; R_1 \to [B_1, R_2, R_3]; R_2 \to [B_1, R_1, R_3]; R_3 \to [B_1, R_1, R_2]

So, the selection is:

Urn\ 1 = 4 * 3

Urn\ 1 = 12

<u>For urn 2</u>

There are 4 balls in urn 2

n = \{B_2,B_3,R_4,R_5\}

Each of the balls has 3 subsets. i.e.

B_2 \to [B_3, R_4, R_5]; B_3 \to [B_2, R_4, R_5]; R_4 \to [B_2, B_3, R_5]; R_5 \to [B_2, B_3, R_4]

So, the selection is:

Urn\ 2 = 4 * 3

Urn\ 2 = 12

Total number of outcomes is:

Total = Urn\ 1 + Urn\ 2

Total = 12 + 12

Total = 24

5 0
3 years ago
Please please help!!!
Rashid [163]

Answer:

  1/2

Step-by-step explanation:

cos(θ) = √(1 -sin(θ)²) = √(1 -3/4) = √(1/4)

cos(θ) = 1/2

3 0
3 years ago
Explain how using basic facts can help you find 10×20×30×40 mentally?
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So all you have to do is take the first numbers of each multiple and multiply them. 
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Now you just add the 4 zeros to your answer. 
240,000 

Our answer even checks! 
10 x 20 x 30 x 40 = 240,000 

Good Luck! :)
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solmaris [256]

Answer:

5 children

Step-by-step explanation:

7 adults = $70

5 children = $25

total= 12 people

○○○○○○○○○○○○○○○

therefore 5 children went

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5 0
3 years ago
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