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3 years ago

14

3a−1=2a show work please

1 answer:

Stels [109]3 years ago

7 0

Answer: Your answer is 1.

Step-by-step explanation: Simplify both sides of the equation, then isolate the variable, A = 1

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Suppose you have 3 pieces of string measuring 6 inches, 9 inches, and 12 inches. How many unique triangles can you form with the

siniylev [52]

A triangle should have 3 points and 3 sides. Let say that the point is ABC. Then the sides would be AB, AC and BC.
There are 3 strings with a different length that can be put into the sides. Assuming the string can be used once, then the possible way would be:
3!/(1+3-3)!= 3!/1!= 3*2*1= 6 ways

8 0

3 years ago

What’s the answer to this thank u for ur help:)

goldfiish [28.3K]

Answer:

b. DAC≅DBC

Step-by-step explanation:

∠DCB≅∠DCA=90° as they are right angles at the perpendicular lines

DC=DC reflexive property(they are the same line)

AC=CB they are both the radius of the same circle

DAC≅DBC due to SAS(Side angle Side)

6 0

3 years ago

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The distance a bike travels varies directly as the amount of time the bike has been ridden. Angela is riding her bike. If she tr

Levart [38]

Answer:

420 miles

Step-by-step explanation:

60 ×7=420

thank

4 0

3 years ago

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2995 divided by 27 but estimated

Vinil7 [7]

Answer: 110

Step-by-step explanation:

6 0

3 years ago

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Find the approximate area between the curve f(x) = -4x² + 32x and on the x-axis on the interval [0,8] using 4 rectangles. Use th

Doss [256]

Split up the interval [0, 8] into 4 equally spaced subintervals:

[0, 2], [2, 4], [4, 6], [6, 8]

Take the right endpoints, which form the arithmetic sequence

$r_i=2+\dfrac{8-0}4(i-1)=2i$

where 1 ≤ <em>i</em> ≤ 4.

Find the values of the function at these endpoints:

$f(r_i)=-4{r_i}^2+32r_i=-16i^2+64i$

The area is given approximately by the Riemann sum,

$\displaystyle\int_0^8f(x)\,\mathrm dx\approx\sum_{i=1}^4f(r_i)\Delta x_i$

where $\Delta x_i=\frac{8-0}4=2$ ; so the area is approximately

$\displaystyle2\sum_{i=1}^4(-16i^2+64i)=-32\sum_{i=1}^4i^2+128\sum_{i=1}^4i=-32\cdot\frac{4\cdot5\cdot9}6+128\cdot\frac{4\cdot5}2=\boxed{320}$

where we use the formulas,

$\displaystyle\sum_{i=1}^ni=\frac{n(n+1)}2$

$\displaystyle\sum_{i=1}^ni^2=\frac{n(n+1)(2n+1)}6$

6 0

3 years ago