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Setler79 [48]
3 years ago
10

How many moles of argon are equal to 3.01×1023 atoms

Chemistry
1 answer:
tiny-mole [99]3 years ago
5 0
To convert from atoms of argon to moles of argon, you need to divide by Avogadro's constant.

3.01*10^23 atoms *(1 mole/6.022*10^23 atoms) = 0.500 moles Ar

0.500 moles of Argon is equal to 3.01*10^23 atoms of Argon.
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PLEASE HELP FOR THIS ASSIGNMENT
mars1129 [50]
<h2>Steps:</h2>
  • Remember that Density = mass/volume, or D = m/v

So firstly, we have to find the volume of the rock. To do this, we need to subtract the volume of water A from the volume of the water B. In this case:

  • Water A = 30 mL
  • Water B = 40 mL
  • 40 mL - 30 mL = 10 mL

<u>The volume of the rock is 10 mL.</u>

Now that we have the volume, we can plug that and the density of the rock into the density equation to solve for the mass.

3.678=\frac{m}{10}

For this, multiply both sides by 10:

36.78=m

<h2>Answer:</h2>

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3 years ago
PH CHEM, PLEASE HELP QUICK! NO LINKS/VIRUSES PLEASE!
Contact [7]

Answer:

The pH of the solution is 11.48.

Explanation:

The reaction between NaOH and HCl is:

NaOH  +  HCl  →  H₂O  +  NaCl

From the reaction of 3.60x10⁻³ moles of NaOH and 5.95x10⁻⁴ moles of HCl we have that all the HCl will react and some of NaOH will be leftover:

n_{NaOH}} = n_{i_{NaOH}} - n_{HCl} = 3.60 \cdot 10^{-3} moles - 5.95 \cdot 10^{-4} moles = 3.01 \cdot 10^{-3} moles

Now, we need to find the concentration of the OH⁻ ions.

[OH^{-}] = \frac{n_{NaOH}}{V}

Where V is the volume of the solution = 1.00 L                

[OH^{-}] = \frac{n_{NaOH}}{V} = \frac{3.01 \cdot 10^{-3} moles}{1.00 L} = 3.01 \cdot 10^{-3} mol/L

Finally, we can calculate the pH of the solution as follows:

pOH = -log([OH^{-}]) = -log(3.01 \cdot 10^{-3}) = 2.52

pH + pOH = 14

pH = 14 - pOH = 14 - 2.52 = 11.48

Therefore, the pH of the solution is 11.48.

I hope it helps you!

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Answer:1.

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Explanation:

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