Question

A sample of NO2 in a 1550 mL metal cylinder at 70.26 kPa has its temperature changed from 480oC to -237oC while its volume is simultaneously changed by a piston to 5114 mL. What is the final pressure in kPa?

Answer 1

Answer:

1.02KPa

Explanation:

The following were obtained from the question:

V1 = 1550mL

P1 = 70.26kPa

T1 = 480°C = 480 + 273 = 753K

T2 = -237°C = - 237 + 273 = 36K

V2 = 5114mL

P2 =?

The final pressure can obtain as follows:

P1V1/T1 = P2V2/T2

(70.26x1550)/753 = (P2x5114)/36

Cross multiply to express in linear form as shown below:

P2 x 5114 x 753 = 70.26 x 1550 x 36

Divide both side by 5114 x 753

P2 = (70.26x1550x36)/(5114x753)

P2 = 1.02KPa

Therefore, the final pressure is 1.02KPa