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Firlakuza [10]
3 years ago
8

3.4 moles of solid CuSO4 is added to 1.8 L of water and allowed to dissolve. Will all the solid dissolve?

Chemistry
1 answer:
ludmilkaskok [199]3 years ago
8 0

Answer:

                     Yes, all the solid will dissolve.

Explanation:

                    To solve this problem we will first find the solubility of CuSO₄ at given temperature (in this case we will assume the temperature to be 20 °C. According to reported data 37.8 g of CuSO₄ can be dissolved in 100 ml of H2O at 20 °C.

                    While we are provided with moles of CuSO₄ and volume is given in Liters. So, we will convert moles to mass as,

                                   Mass  =  Moles × Molar Mass

                                   Mass  =  3.4 mol × 159.60 g/mol

                                   Mass  =  542.64 g

Secondly, we will convert Liters to milliliters as,

                                  Milliliters  =  Liters × 1000

                                  Milliliters  =  1.8 × 1000

                                  Milliliters  =  1800 ml

Therefore,

According to reference data,

                     37.8 g CuSO₄ dissolves in  =  100 ml of water

So,

            542.64 g CuSO₄ will dissolve in  =  X ml of water

Solving for X,

                      X  =  542.64 g × 100 ml / 37.8 g

                      X =  1435.55 ml of Water

This means that we are provided with greater amount of water (i.e. 1800 m). Hence, the given amount of CuSO₄ will completely dissolve in 1.8 L of water and the solution formed is <em>unsaturated</em> and can dissolve further CuSO₄.

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Answer;

C7H14O2

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Mass of Hydrogen  = 2/18 × 1.116 g

                            =  0.124 g

Mass of oxygen = 1.152 - (0.7435 + 0.124)

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Moles of hydrogen; 0.124/1 = 0.124 moles

Moles of oxygen;  0.2845/16 = 0.01778 moles

Ratios ; 0.06196/0.01778 ; 0.124/0.01778 : 0.01778/0.01778

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To make them whole numbers ; we multiply the ratios by 2  to get;

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