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Firlakuza [10]
3 years ago
8

3.4 moles of solid CuSO4 is added to 1.8 L of water and allowed to dissolve. Will all the solid dissolve?

Chemistry
1 answer:
ludmilkaskok [199]3 years ago
8 0

Answer:

                     Yes, all the solid will dissolve.

Explanation:

                    To solve this problem we will first find the solubility of CuSO₄ at given temperature (in this case we will assume the temperature to be 20 °C. According to reported data 37.8 g of CuSO₄ can be dissolved in 100 ml of H2O at 20 °C.

                    While we are provided with moles of CuSO₄ and volume is given in Liters. So, we will convert moles to mass as,

                                   Mass  =  Moles × Molar Mass

                                   Mass  =  3.4 mol × 159.60 g/mol

                                   Mass  =  542.64 g

Secondly, we will convert Liters to milliliters as,

                                  Milliliters  =  Liters × 1000

                                  Milliliters  =  1.8 × 1000

                                  Milliliters  =  1800 ml

Therefore,

According to reference data,

                     37.8 g CuSO₄ dissolves in  =  100 ml of water

So,

            542.64 g CuSO₄ will dissolve in  =  X ml of water

Solving for X,

                      X  =  542.64 g × 100 ml / 37.8 g

                      X =  1435.55 ml of Water

This means that we are provided with greater amount of water (i.e. 1800 m). Hence, the given amount of CuSO₄ will completely dissolve in 1.8 L of water and the solution formed is <em>unsaturated</em> and can dissolve further CuSO₄.

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stealth61 [152]

Answer:

aa

Explanation:

There is a lowercase a on both sides.

4 0
2 years ago
An oxide of aluminum contains 0.545 g of Al and 0.485 g of O. Find the empirical formula
uysha [10]

Answer:

The answer is: <u>Al2O3</u>

Explanation:

The data they give us is:

  • 0.545 gr Al
  • 0.485 gr O.

To find the empirical formula without knowing the grams of the compound, we find it per mole:

  • 0.545 g Al * 1 mol Al / 27 g Al = 0.02 mol Al
  • 0.485 g O * 1 mol O / 16 g O = 0.03 mol O

Then we must divide the results obtained by the lowest result, which in this case is 0.02:

  • 0.02 mol Al / 0.02 = 1  Al
  • 0.03 mol O / 0.02 = 1.5  O

Since both numbers have to give an integer, multiply by 2 until both remain integers:

  • 1Al * 2 = 2Al
  • 1.5O * 2 = 3O

Now the answer is given correctly:

  • Al2O3

8 0
3 years ago
For the reaction
azamat

Answer:

Mass = 5.56 g

Explanation:

Given data:

Mass of Cl₂ = 4.45 g

Mass of NaCl produced = ?

Solution:

Chemical equation:

2Cl₂ + 4NaOH     →   3NaCl + NaClO₂ + 2H₂O

Number of moles of Cl₂:

Number of moles = mass/molar mass

Number of moles = 4.45 g/ 71 g/mol

Number of moles = 0.063 mol

Now we will compare the moles of Cl₂ with NaCl.

                  Cl₂         :         NaCl

                    2          :          3

                 0.063      :        3/2×0.063 =0.095 mol

Mass of NaCl:

Mass = number of moles × molar mass

Mass = 0.095 mol × 58.5 g/mol

Mass = 5.56 g

7 0
2 years ago
Given the reaction _K(s) +_ Cl2(g) → _KCl(s) what is the amount of K, in grams, needed to completely react with 2 moles of Cl2(g
damaskus [11]

Answer:

156.4g K

Explanation:

I'm not sure if it is correct but I think it should be this

What do we know so far?: 2K + 1Cl2 -> 2KCl, 2 mol of Cl2

What are we looking for?: #g of K

What is the ratio of K to Cl2?: 2:1

Set up equation: 2molCl2 x \frac{2mol K}{1 mol Cl2}

Cancel unwanted units: 2 x \frac{2mol K}{1}

Answer we got: 2 x 2mol K = 4mol K

Converting moles to grams: 4 x 39.1 (molar mass of K) = 156.4g K

3 0
3 years ago
Nitrogen (N) has an atomic number of 7 and an atomic mass of 14. Which of the following correctly shows the electron arrangement
adell [148]

7 protons means that N atom has 7 electrons

1st level can have only 2 e⁻, and we have left over of 7-2=5 e⁻, that will go on the second level.

B. 2,5

3 0
3 years ago
Read 2 more answers
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