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sdas [7]
2 years ago
11

Given the amount of camphor (200mg) we are using in this experiment, please determine how many mg of sodium borohydride to use i

n this reaction. We would like you to use 5.2 molar equivalents of this reagent. This means 5.2 times the mmol of camphor we are using. As an example: for 110.0 mg of camphor,142 mg of NaBH4 would be used (see if you can confirm this result). For complete credit, your work needs to be clearly drawn out!
Chemistry
1 answer:
swat322 years ago
7 0

Answer:

Explanation:

From the given information:

Camphor may be reduced as readily in the presence of sodium borohydride(NaHB4). The resulting compound which is stereoselective requires 1 mole of sodium borohydride (NaHB4) to reduce 1 mole of camphor in this reaction. The reaction is shown below.

Through the reduction process of camphor, the reducing agent can reach the carbonyl face with a one-carbon linkage. The product stereoisomer is known as borneol.

If the molecular weight of camphor = 152.24 g/mol

and it mass = 200 mg

The its no of moles = 200 mg/ 152.24 g/mol

= 1.3137 mmol

Now the amount of the required mmol for NaBH4 to be consumed in the reaction = 5.2 × 1.3137 mmol

= 6.831 mmol

since the molar mass of NaBH4 = 37.83 g/mol

Then, using the same formula:

No of moles = mass/molar mass

mass = No of moles × molar mass

mass = 6.831 mmol × 37.83 g/mol

mass of NaBH4 used = 258.42 mg  

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I think the answer for this is 4702.5 J/g*k Depending on if it is water as a solid liquid or gas. I used water as a liquid when I solved it. J=(75g)(4.18 J/g*k)(15K)
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3 years ago
Enter an abbreviated electron configuration for magnesium: Express your answer in complete form, in order of increasing energy.
stiks02 [169]

Answer:

1s2, 2s2,2p6,3s2

Explanation:

6 0
3 years ago
Read 2 more answers
Students in a chemistry class added 5 g of Zinc to 50 g of hydrochloric acid. A chemical reaction occurred that produced zinc ch
Vinil7 [7]

Answer:

Mass = 11 g

Explanation:

Given data:

Mass of Zn = 5 g

Mass of HCl = 50 g

Mass of hydrogen gas produced = 6 g

Mass of zinc chloride produced = ?

Solution:

Chemical equation:

Zn + 2HCl    →   ZnCl₂ + H₂

Number of moles of Zn:

Number of moles = mass / molar mass

Number of moles = 5 g / 65.38 g/mol

Number of moles = 0.08 mol

Number of moles of HCl :

Number of moles = mass / molar mass

Number of moles = 50 g / 36.5 g/mol

Number of moles = 1.4 mol

Now we will compare the moles of both reactant with zinc chloride.

              Zn           :           ZnCl₂

               1             :             1

              0.08       :        0.08

            HCl          :         ZnCl₂

              2            :           1

             1.4          :         1/2×1.4 =0.7 mol

The number of moles of zinc chloride produced by Zn are less so it will limiting reactant.

Mass of zinc chloride:

Mass = number of moles × molar mass

Mass = 0.08 mol × 136.3 g/mol

Mass = 11 g

5 0
3 years ago
4. Al2O3 (s) + 6HCl (aq) → 2AlCl3 (aq) + 3H20(1) Find the mass of AlCl3 that is produced when 10.0 grams of Al2O3 react with 10.
slava [35]

Answer:

Are produced 12,1 g of AlCl₃ and 5,33 g of Al₂O₃ are left over

Explanation:

For the reaction:

Al₂O₃ (s) + 6 HCl (aq) → 2AlCl₃ (aq) + 3H₂0(l)

10,0g of Al₂O₃ are:

10,0g ₓ\frac{1mol}{102g} = <em>0,0980 moles</em>

And 10,0g of HCl are:

10,0 gₓ\frac{1mol}{36,5g} = <em>0,274 moles</em>

<em />

For a total reaction of 0,274 moles of HCl you need:

0,274×\frac{1molesAl_{2}O_3}{6 mole HCl} = <em>0,0457 moles of Al₂O₃</em>

Thus, limiting reactant is HCl

The grams produced of AlCl₃ are:

0,274 moles HCl ×\frac{2 moles AlCl_{3}}{6 moles HCl} × 133\frac{g}{mol} = <em>12,1 g of AlCl₃</em>

<em />

The moles of Al₂O₃ that don't react are:

0,0980 moles - 0,0457 moles =<em> </em>0,0523 moles

And its mass is:

0,0523 molesₓ\frac{102g}{1mol} = <em>5,33 g of Al₂O₃ </em>

<em />

I hope it helps!

7 0
3 years ago
A super slow snail can travel 2.2cm in one minute. How far (in pm) can it travel in 24 hours? Please round to appropriate number
Cloud [144]

Answer : The distance covered by slow snail in 24 hours is 3.2\times 10^{13}pm

Explanation :

As we are given that the a slow snail can travel 2.2 cm in 1 minute. Now we have to calculate the distance covered by slow snail in 24 hours.

First we have to convert 24 hours in minutes.

Conversion used : (1 hour = 60 minutes)

As, 1 hour = 60 minutes

So, 24 hour = 24 × 60 minutes

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Now we have to calculate the distance covered by slow snail in 24 hours.

In 1 minute, the distance covered by slow snail = 2.2 cm

In 1440 minute, the distance covered by slow snail = 1440 × 2.2 cm

                                                                                     = 3168 cm

                                                                                     = 3.2\times 10^3cm

Now we have to convert 'cm' into 'pm'.

Conversion used : 1cm=10^{10}pm

As, 1cm=10^{10}pm

So,  3.2\times 10^3cm=\frac{3.2\times 10^3cm}{1cm}\times 10^{10}pm=3.2\times 10^{13}pm

Therefore, the distance covered by slow snail in 24 hours is 3.2\times 10^{13}pm

4 0
3 years ago
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