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notka56 [123]
3 years ago
8

What is a solid figure with 1 circular base and one curved surface

Mathematics
2 answers:
Novosadov [1.4K]3 years ago
8 0
A solid figure with a circular base and a curved surface would be a <em><u /></em><u />cone.

I hope this helps you! Good luck :)

natima [27]3 years ago
5 0
I believe that the figure you are talking about a cone. A cone could be right since the bottom is circular and the other parts of the surface is curved.
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An acute angle θ is in a right triangle with sin θ = five sixths. What is the value of cot θ?
Molodets [167]
<span>The value of cot is √13/6</span>
6 0
3 years ago
Points P and Q belong to segment AB . If AB = a, AP = 2PQ = 2QB, find the distance: midpoints between AP QB
Digiron [165]

Answer: The distace between midpoints of AP and QB is \frac{a}{8}.

Step-by-step explanation: Points P and Q are between points A and B and the segment AB measures a, then:

AP + PQ + QB = a

According to the question, AP = 2 PQ = 2QB, so:

PQ = \frac{AP}{2}

QB = \frac{AP}{2}

Substituing:

AP + 2*(\frac{AP}{2}) = a

2AP = a

AP = \frac{a}{2}

Since the distance is between midpoints of AP and QB:

2QB = AP

QB = \frac{AP}{2}

QB = \frac{a}{2}*\frac{1}{2}

QB = \frac{a}{4}

MIdpoint is the point that divides the segment in half, so:

<u>Midpoint of AP</u>:

\frac{AP}{2} = \frac{a}{2}*\frac{1}{2}

\frac{AP}{2} = \frac{a}{4}

<u>Midpoint of QB</u>:

\frac{QB}{2} = \frac{a}{4}*\frac{1}{2}

\frac{QB}{2} = \frac{a}{8}

The distance is:

d = \frac{a}{4} - \frac{a}{8}

d = \frac{a}{8}

4 0
3 years ago
What is 2/3 divided by 2/9
serg [7]
Your answer: 2/3/2/9 = 0.037037037037037
4 0
3 years ago
Read 2 more answers
c.) The sonar of a navy cruiser detects a submarine that is 4000 feet from the cruiser. The angle between the water line and the
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Answer:

2236.77 feets

Step-by-step explanation:

From the attached picture, we are to find x, which is the vertical depth of the submarine.

Using trigonometry based on the illustration in the diagram:

Sinθ = opposite / hypotenus

Sinθ = x (depth of submarine) / distance from ship (4000)

Hence,

Sinθ = x / 4000

θ = 34°

Sin34 = x / 4000

0.5591929 * 4000 = x

2236.7716 = x

Hence, depth of submarine = 2236.77 feets

7 0
2 years ago
Felix was asked whether the following equation is an identity:<br> (x^2-1)^2=(x^2-1)+(2x)^2
Rudiy27

Answer:

The answer is no

Step-by-step explanation:

The equation is not an identity

7 0
3 years ago
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