<span>The value of cot is √13/6</span>
Answer: The distace between midpoints of AP and QB is
.
Step-by-step explanation: Points P and Q are between points A and B and the segment AB measures a, then:
AP + PQ + QB = a
According to the question, AP = 2 PQ = 2QB, so:
PQ =
QB = 
Substituing:
AP + 2*(
) = a
2AP = a
AP = 
Since the distance is between midpoints of AP and QB:
2QB = AP
QB = 
QB = 
QB = 
MIdpoint is the point that divides the segment in half, so:
<u>Midpoint of AP</u>:


<u>Midpoint of QB</u>:


The distance is:
d = 
d = 
Your answer: 2/3/2/9 = 0.037037037037037
Answer:
2236.77 feets
Step-by-step explanation:
From the attached picture, we are to find x, which is the vertical depth of the submarine.
Using trigonometry based on the illustration in the diagram:
Sinθ = opposite / hypotenus
Sinθ = x (depth of submarine) / distance from ship (4000)
Hence,
Sinθ = x / 4000
θ = 34°
Sin34 = x / 4000
0.5591929 * 4000 = x
2236.7716 = x
Hence, depth of submarine = 2236.77 feets
Answer:
The answer is no
Step-by-step explanation:
The equation is not an identity