The sample % of these two populations would be 100/size (of student body at each school) x 100 so this would compare the two student bodies preferences for the particular type of candy bar. However, the actual % of the whole student body at each school would be a factor also. If the high school only had 200 students then this would be 50% representative but if the middle school had say 500 students this would only be 20% representative so this would have to be taken into account too. It might be more representative to have the same % of the student bodies respectively for the sample.
So first create and define your variables:
Z = amount of zebra fish
N = amount of neon tetras
Now create your equations:
2z+2.15n=31.20
z+n=15
This is your system. There are multiple methods to use but in this problem I’ll use the substitution method by simplifying the bottom equation.
2z+2.15n=31.20
z=15-n
Now I’ll plug the bottom equation into the top one.
2(15-n)+2.15n=31.20
And just solve from here.
30-2n+2.15n=31.20
0.15n=1.20
n=8
So he bout 8 neon tetras, and 15-8= 7, so he bought 7 zebra fish
Answer:
Step-by-step explanation:
8
Answer:
5)surface =2(lb*bh*hl)
=2(12*4+4*4+4*12)
=2(48+16+48)
=2(96+16)
=2*112
=224inc^2
6)surfacearea=2*pi*r(r+h)
=2*3.14*2(2+1)
=6.28*2*3
=6.28*6
=37.68m^2
Answer:
5
Step-by-step explanation:
10÷2-3 (5×0)
