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3 years ago

NEED QUICKLY!!!! -Please solve the image below

Mathematics

1 answer:

AnnyKZ [126]3 years ago

4 0

Yes,this is a doozy.

 -3 (y - 5) = 15

Eliminate the parentheses on the left side:

 -3(y) -3(-5) = 15

 -3y + 15 = 15

Subtract 15 from each side:

 -3y = 0

Divide each side by -3 :

  y = 0

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What equation represents a circle whose center is located at (-6,2) and whose radius is 10 units?

Anna [14]

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2 years ago

what is the y-intercept of the line perpendicular to the line y=-3/4x+5 that includes the point (-3,-3)?

Deffense [45]

Answer:

Step-by-step explanation:

For this question, your friend is the point-slope form.

Point-slope form = $y-y_1 = m(x-x_1)$

The only variables you replace are m = slope, y1 = y of a given point, and x1 = x of a given point.

First, we need to find the slope that is perpendicular to the equation $y=-\frac{3}{4}x+5$

An equation that is perpendicular to another equation have to be negative reciprocals (negative inverse) of each other.

If the slope is 3, then the negative reciprocal of 3 is $-\frac{1}{3}$ .

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We will use the negative reciprocal as m since we are trying to find the equation of line that includes (-3, -3) and is perpendicular to the other equation.

We will use point slope form using the (-3, -3) points and negative reciprocal as m.

$y-y_1 = m(x-x_1)\\y-(-3) = \frac{4}{3} (x-(-3))\\y+3=\frac{4}{3}(x+3)$

Now, we need to convert this into slope-intercept form. The reason why we need to do this is because y = mx + b, where b is the y-intercept. To do this, solve for y - or in other words, isolate y..

$y+3=\frac{4}{3}(x+3)\\y+3=\frac{4x}{3}+4\\y+3-3=\frac{4x}{3}+4-3\\y=\frac{4}{3}x+1$

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VikaD [51]

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