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Aliun [14]
3 years ago
13

Which of the following is not an intentional way of introducing nonnative species into an ecosystem?

Biology
1 answer:
Alchen [17]3 years ago
3 0

Answer:e

Explanation:duh

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Which of the following would best help to maintain homeostasis when a person's internal body temperature reaches 97.5 degrees Fa
Step2247 [10]
C) dilation of capillaries 
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Which group does not contain animals that are arthropods?
vaieri [72.5K]

Answer:

arachnids _c

Explanation:

that is the right answer I believe.

6 0
3 years ago
Do plants have to do cellular resperation? why or why not?
LUCKY_DIMON [66]

Explanation:

Like all other organisms, plants require energy to grow and thrive in their environment. The process of cellular respiration allows plants to break down glucose into ATP.

Although plants use photosynthesis to produce glucose, they use cellular respiration to release energy from the glucose.

3 0
3 years ago
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What are the possible blood types among the children of parents that are IAIB and ii? A. types A and B B. types A, B, and AB C.
balandron [24]

Answer:

The correct answer would be A. types A and B.

In ABO blood group, blood group is determined by three alleles I^{A},I^{B}, and i.

I^{A} and I^{B} are codominant to each other whereas i is recessive to the other two.

The genotype of one parent is I^{A}I^{B}. So, two types of gametes would be produced I^{A} and I^{B}

The genotype of second parent is ii. So, the gamete produced would be i.

The cross would result in the production of offspring with genotype I^{A}i and I^{B}i.

Thus, the phenotype of the offspring would be blood group A and B.

5 0
3 years ago
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Two true-breeding stocks of pea plants are crossed. One parent has red, axial flowers and the other has white, terminal flowers;
gogolik [260]

Answer:

187.5 or rounded off to 188 white, terminal flowers

Explanation:

Let red=R and white=r where R>r; axial=A and terminal=a where A>a

The parents are true-breeding which means that they are homozygous.

P: RRAA x rraa

F1: RrAa

We then cross two plants from the F1 generation

RrAa x RrAa

To find out the probability we look at the different traits individually

Rr x Rr

yielding 1/4 RR (red), 1/2 Rr (red), 1/4 rr (white)

Aa x Aa

yielding 1/4 AA (axial), 1/2 Aa (axial), 1/4 aa (terminal).

We determine which F2 genotypes would allow for red, terminal flowers.

RRaa and Rraa

Then we use the multiplication rule to determine the probability of these occurring

RRaa: 1/4 x 1/4 = 1/16

Rraa: 1/2 x 1/4 = 1/8

Next we use the addition rule

1/16 + 1/8 = 3/16

To find out the number of these plants within the 1000 F2 plants we multiply the probability with 1000

3/16 x 1000= 187.5 red, terminal flowers

8 0
3 years ago
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