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2 years ago

Which of the following is a way to advocate for avoiding tobacco?

2 answers:

7 0

To advocate for avoiding tobacco, you should start by setting an example of yourself. If you are ever offered tobacco products, you should have the courage and confidence to say no. You can also educate others on the dangers of tobacco and help them understand that smoking tobacco isn't worth the risks.

Hope this helps! :)

docker41 [41]2 years ago

6 0

Saying no when poeple offer it to you

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Which is an example of a cognitive milestone?

Zigmanuir [339]

Answer:

C. Stacking rings by size

Explanation:

Similar to a puzzle a young child would have to judge the sizes and gather and organize that information.

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2 years ago

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2 years ago

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The skin has multiple functions. Which of the following is not one of the skin functions. A) regulates body temperature B) works

Viktor [21]

Answer:

I think the answer is A. Hope it helps!!!!!

Explanation:

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3 years ago

Highlight two words that mean "tired" in this excerpt from Anne Bradstreet's "As Weary Pilgrim, Now at Rest."

UkoKoshka [18]

Answer:

Weary and Rest

Explanation:

Weary means the feeling or showing tiredness. This makes it an answer.

The other word would be rest(to show that if you are tired, you need rest).

You could also use process of elimination:

As isn't the word,

Pilgrim means "explorer",

Now isn't the word,

and at isn't the word.

That leaves two words: Weary and Rest

Tell me if this answer is satisfactory!

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2 years ago

Which of the following BEST describes a body in equilibrium?

sukhopar [10]

$\textsf {\large{\underline { \underline {SOLUTION:-}}}}$

⇰Let O be the point of observation on the ground OX.

⇰Let A and B be the two positions of the jet.

$\bf➠Then, \angle XOA=60⁰ \: and \: \angle \: XOB=30⁰ \\ \\$

$\bf ➠Draw \: AL \perp \: OX \: and \: BM \perp \: OX \\ \\$

$\bf \:⇰ Let \: AL=BM=h \: meters. \\ \\$

$\bf \: ⇰ \: Speed \: of \: Jet = 720 \: km/hr\\$

$\bf = \huge( \small \: 720 \times \frac{5}{18} \huge) \small \: m / s\\$

$\bf = 200 \: m/s$

$\bf \:➥ Time \: taken \: to \: cover \: the \: distance \: AB=15 \: sec \\ \\$

$\bf➥ Distance \: covered =(speed×time) \\ \\$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \bf = (200 \times 15)m = 3000m \\ \\$

$\bf \therefore LM=AB=3000m \\ \\$

${ \bf \: ⇰ \: Let \: OL} = x \: \bf m \\ \\$

$\bf➥From \: right \: \triangle OLA, \: we \: have: \\$

$\bf \frac{OL}{AL} =cot \: 60⁰= \frac{1}{ \sqrt{3} } \implies \frac{x}{h} = \frac{1}{ \sqrt{3} } \\ \\$

$\bf \implies \: x = \frac{h}{ \sqrt{3} } \: \: \: \: \: \: \: ....(1) \\ \\$

$\bf \:➥ From \: right \: \triangle \: OMB,we \: have: \\$

$\bf\frac{OM}{BM} =cot30⁰= \sqrt{3} \\ \\$

$\bf \implies \: \frac{x + 3000}{h} = \sqrt{3} \\ \\$

$\bf[ \boxed{➯OM=OL+LM=OL+AB=(x+3000)m \: and \: BM=h \: m]}$

$\bf \implies \: x + 3000 = \sqrt{3} h \\$

$\bf \implies \: x = ( \sqrt{3} h - 3000) \: \: \: \: \: \: ....(2) \\$

⇰ Equating the value of x from (1) and (2),we get;

$\bf \: \sqrt{3} h - 3000 = \frac{h}{ \sqrt{3} } \\ \\$

$\implies \bf \: 3h - 3000 \sqrt{3} = h \\$

$\bf \implies \: 2h = (3000 \times \sqrt{3} ) = (3000 \times 1.762) \\$

$\bf \implies \: h = (3000 \times 0.866) = 2598 \\ \\$

$\bf \:➥ Hence \: ,the \: required \: height \: is \: \boxed{ \boxed{ \bf2598 \: m.}} \\ \\$

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4 0

2 years ago

Read 2 more answers