Use x = 3 to identify the value of each expression. Exponent Value of expression

Scott burned 20 calories per minute jogging for x minutes and 5 calories per minute for biking for y minutes. He spent a total o

stiv31 [10]

Answer:

x = 112

Step-by-step explanation:

We can create two equations 1. one that calculates calories burned and 2.another that calculates minutes:

20*x + 5*y = 1200

x + y = 120

Then we can solve for x

x = 120 - y

then we can plug that into the top equation:

20(120 - y) + 5y = 1200

divide by 5:

4(120 - y) + y = 240

distribute:

480 - 4y + y = 240

and then do all that combining like factors what not and simplify and solve:

480 - 3y = 240

-3y = -240

y = 8

NOW WE CAN JUST PLUG IN THE ANSWER FOR Y TO FIND X

8+x =120

x = 112

7 0

3 years ago

Given a data set consisting of 33 unique whole number observations, its five-number summary is:

Lemur [1.5K]

Answer:

given a data set of 33 unique whole number observation,its five number sumary is [16, 29, 40 ,54, 67]

Step-by-step explanation:

The p-th percentile in an ordered (from low to high) data set is a value such that p% of the data is less than that value. The quartiles of a data set are the 25th, 50th and 75th percentiles. (The 25th percentile is usually called the first quartile, the 50th percentile is usually called the median, and the 75th percentile is usually called the third quartile.)

The formula for finding the location (or position) of the (approximate) pth percentile in an ordered (from low to high) data set is

L p=(n+1).p/100

For example, in the data set [2,4,6,8,10,12,14,16,18]

the (approximate) 60th percentile is located at position

L 60=(9+1).60/100=6

that is, the sixth data point (the value 12) is at the (approximate) 60th percentile.(Actually, only 55.6% of the data is below a 12.)

3 0

3 years ago

Assume a simple random sample of 10 BMIs with a standard deviation of 1.186 is selected from a normally distributed population o

kirza4 [7]

Answer:

a) H0: $\sigma = 1.34$

H1: $\sigma \neq 1.34$

b) $df = n-1= 10-1=9$

And the critical values with $\alpha/2=0.005$ on each tail are:

$\chi_{\alpha/2}= 1.735, \chi_{1-\alpha/2}= 23.589$

c) $t=(10-1) [\frac{1.186}{1.34}]^2 =7.05$

d) For this case since the critical value is not higher or lower than the critical values we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true deviation is not significantly different from 1.34

Step-by-step explanation:

Information provided

n = 10 sample size

s= 1.186 the sample deviation

$\sigma_o =1.34$ the value that we want to test

$p_v$ represent the p value for the test

t represent the statistic (chi square test)

$\alpha=0.01$ significance level

Part a

On this case we want to test if the true deviation is 1,34 or no, so the system of hypothesis are:

H0: $\sigma = 1.34$

H1: $\sigma \neq 1.34$

The statistic is given by:

$t=(n-1) [\frac{s}{\sigma_o}]^2$

Part b

The degrees of freedom are given by:

$df = n-1= 10-1=9$

And the critical values with $\alpha/2=0.005$ on each tail are:

$\chi_{\alpha/2}= 1.735, \chi_{1-\alpha/2}= 23.589$

Part c

Replacing the info we got:

$t=(10-1) [\frac{1.186}{1.34}]^2 =7.05$

Part d

For this case since the critical value is not higher or lower than the critical values we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true deviation is not significantly different from 1.34

5 0

3 years ago

13 divided by $85.02

Salsk061 [2.6K]

The answer is 0.15290519877

6 0

3 years ago

Read 2 more answers

2x + 3 > 13 x= 0 is this true? O True O False

omeli [17]

False.

Replace x with 0 and solve:

2(0) + 3 = 0+ 3 = 3

3 is not greater than 13 so the answer is false.

5 0

2 years ago