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madreJ [45]
2 years ago
5

A chain has 47 links. 13 link from one end is rusted. From the other end 17 link is also rusted. How many links lie between thes

e tw rusted links?​
Mathematics
2 answers:
Butoxors [25]2 years ago
7 0

Answer:

17

Step-by-step explanation:

olganol [36]2 years ago
6 0

Answer:

17 links

Step-by-step explanation:

<em>1. </em>13 Links and 17 links are rusted. Since we need to find out the number of links that are not rusted, we need to add 13+17.

<em>a.</em><em>  13  + 17 = 30</em>

2. Now since we added the number of lines rusted, we now should subtract the ones rusted and the one not rusted to get the answer.

a. 47-30 = 17

FINAL ANSWER: 17

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Long division<br> 3x+1/6x^6+5x^5+2x^4-9x^3+7x^2-10x+2
inna [77]
(6 x^{6}+5x^{5}+2x^{4}-9x^{3}+7x^{2}-10x+2) / (3x+1)

We divide first number from first parenthesis with first number from second parenthesis. Then the resulting number we multiply by all numbers in second parenthesis and substract from first parenthesis.

6 x^{6}/3x = 2 x^{5} \\  \\ 6 x^{6}+5x^{5}+2x^{4}-9x^{3}+7x^{2}-10x+2 - 6 x^{6} -2 x^{5} = 3x^{5}+2x^{4}-9x^{3}+7x^{2}-10x+2\\

We repeat previous steps until we run out of numbers:
3x^{5}/3x=x^{4} \\ \\ 3x^{5}+2x^{4}-9x^{3}+7x^{2}-10x+2-3x^{5}-x^{4}= \\ \\ x^{4}-9x^{3}+7x^{2}-10x+2 \\ \\ \\ x^{4}/3x= \frac{1}{3} x^{3} \\ \\ x^{4}-9x^{3}+7x^{2}-10x+2-x^{4}- \frac{1}{3} x^{3}= \\ \\ - \frac{28}{3} x^{3}+7x^{2}-10x+2 \\ \\ \\ - \frac{28}{3} x^{3}/3x= - \frac{28}{9} x^{2} \\ \\ - \frac{28}{3} x^{3}+7x^{2}-10x+2+ \frac{28}{3} x^{3}+ \frac{28}{9} x^{2} = \\ \\ \frac{91}{9} x^{2}-10x+2
\frac{91}{9} x^{2}/3x=\frac{91}{27} x \\ \\ \frac{91}{9} x^{2}-10x+2-\frac{91}{9} x^{2}-\frac{91}{27} x= \\ \\ -\frac{361}{27} x+2 \\ \\ \\ -\frac{361}{27} x/3x=-\frac{361}{81} \\ \\ -\frac{361}{27} x+2+\frac{361}{27}x+\frac{361}{27}= \\ \\ \frac{415}{27}

We are left with a number that has no x inside. This is remainder.
The final solution is sum of all these solutions and remainder:
(2 x^{5}+x^{4}+\frac{1}{3} x^{3} - \frac{28}{9} x^{2} +\frac{91}{27} x)+(-\frac{361}{81} )
6 0
3 years ago
Can you help me solve this question
IRINA_888 [86]

Answer: Coordinates: (1,3) length RS: 3 length RT: 2 ST: 3.6

Step-by-step explanation:

a^2+b^2=c^2

3^2+2^2=c^2

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3 0
2 years ago
Please help me ASAP!!
Sati [7]

The answer is D, i.e. the system was solved via elimination


If you multiply the first equation by 5, the system becomes


\left \{ {{-5x-10y=35} \atop {5x-6y=-3}} \right.


If you sum the two equations, you get


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And so if you substitute the second equation of system A with this new equation, you'll get system B.

3 0
3 years ago
Please help with this math problem
VashaNatasha [74]
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(multiply both sides by 3)
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7 0
3 years ago
Read 2 more answers
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ziro4ka [17]

Answer:

3x+18

Step-by-step explanation:

3 (x+6)

Distribute

3x+3*6

3x+18

4 0
3 years ago
Read 2 more answers
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