Question

Solve this equation using the quadratic equation: 3x^2 +4x +2 =0 ( plz show all work)

Answer 1

Standard form
Coeficients are: a = 3; b = 4; c = 2;
Because $b^{2} -4ac = -8$ is negative we get two Complex solutions;
We can use the special Quadratic Formula
x = (-b + or - i$\sqrt{ b^{2}-4ac }$)/(2a); where i = $\sqrt{-1} ;$
Then, x1 = (-4 + i2$\sqrt{2} )/6 = 2(-2 + i \sqrt{2} )/6 = (-2+i \sqrt{2} )/3;$;
In similar way, we obtain x2 =  (-2-i \sqrt{2} )/3;[/tex];