The 2 equations are
-2x + y = -17 ---1)
3x + y = 23 ---2)
we need to have the same coefficient for one of the variables.
Already y variable has the coefficient of 1 for both equations so we can use the equations as it is.
2) - 1) subtract 1) from 2)
3x-(-2x) + y -y = 23-(-17)
5x = 40
x = 8
substituting x = 8 in the 2nd equation
3*8 + y = 23
24 + y = 23
y = -1
solution - (8,-1)
Answer: Each adult’s meal costed $15
Step-by-step explanation:
This situation can be modeled by the following equation:
2a + 3c = 42, where a = the cost of an adult’s meal, and c = the cost of a child’s meal
Since we know from the problem that a child’s meal costs $4, we know c:
2a + 3(4) = 42
At this point, we can just solve the resulting equation for a:
2a + 3(4) = 42
= 2a + 12 = 42 (simplify 3(4))
= 2a = 30 (subtract 12 from both sides)
= a = 15 (divide both sides by 2)
So, the cost of each adult’s meal was $15.
Answer:
416
Step-by-step explanation:
v-lwh
v(10.4)(5)(8)
v- 416 mm
Answer:
1.1587855e+30
Step-by-step explanation:
Answer:
6(a)+14
Step-by-step explanation:
First you need to find f(a) and f(2) separately, then add them together after
f(a) = 6(a)+1
f(2) = 6(2)+1 = 12+1 = 13
so f(a)+f(2) = 6(a)+1+13 = 6(a)+14
