- ATP supplies energy for cellular activities by releasing one of the phosphate group in its molecule
- Cellular activities in living organisms make use of ATP as source of energy
<h3>What is ATP?</h3>
ATP stands for Adenosine triphosphate and it is an energy carrier molecule in living cells of an organism.
The ATP molecule is made up of three components namely;
- Nitrogenous base
- 3 Phosphate groups
- Five carbon sugar
The ATP molecule gains one phosphate group when it stores energy and loses one when it releases energy.
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The question is incomplete. The complete question is:
Question: What is the expected percent change in the DNA content of a typical eukaryotic cell as it progresses through the cell cycle from the start of the G1 phase to the end of the G2 phase
a. -100%
b. -50%
c. +50%
d. +100%
Answer:
d. +100%
Explanation:
S phase comes between G1 and G2 phases of the interphase of a cell cycle. S phase of interphase includes replication of DNA. The process of DNA replication doubles the amount of DNA present in the cell. The newly synthesized DNA is accommodated in the sister chromatids of chromosomes. Therefore, a cell with 2C DNA in the G1 phase would have 4C DNA at the end of the G2 phase. So, there is a +100% increase in the DNA content of a cell as it proceeds from G1 to the end of the G2 phase.
Answer:
Meiosis is a type of cell division that reduces the number of chromosomes in the parent cell by half and produces four gamete cells. The process results in four daughter cells that are haploid, which means they contain half the number of chromosomes of the diploid parent cell
Explanation:
Meiosis begins with a parent cell that is diploid, meaning it has two copies of each chromosome. ... The process results in four daughter cells that are haploid, which means they contain half the number of chromosomes of the diploid parent cell.
Answer:
25% colorblind daughter: 25% colorblind son: 25% carrier daughters with normal vision: 25% normal son.
Explanation:
The genotype of a color-blind man is X^cY and the genotype of the heterozygous carrier female is X^cX. A cross between X^cY and X^cX would produce a progeny in following ratio=
25% colorblind daughter: 25% colorblind son: 25% carrier daughters with normal vision: 25% normal son.
Therefore, the couple is likely to have 50% normal son and 50% affected son. Likewise, the couple is likely to have 50% normal daughters and 50% colorblind daughters.