Answer:
Testcrosses clarify linkage because each phenotypic class of progeny corresponds to each gamete type produced by the dihybrid parent.
Explanation:
- A test cross involves the crossing of an individual with another phenotypically recessive individual so as to determine the zygosity of the former by analyses of the proportions of offspring phenotypes.
- In order to determine linkage, the test cross shows that if the parentals are more than the recombinants, we can say that the two genes such as b and c are genetically linked and therefore, they must be on the same chromosome.
- Also, the test-crosses help to find out which alleles came from which parent.
- By setting up testcrosses in which one parent is homozygous for the recessive alleles of both genes,we can analyze the gene combinations received in the gametes from the other, doubly heterozygous parent.
Answer:
They do not contain chromosomes. (Ans.C).
Explanation:
Cyanobacteria also known as blue-green algae, they are heterogeneous group of photosynthetic prokaryotic organisms. Like prokaryotes such as bacteria, cyanobacteria lack endoplasmic reticulum, mitochondria, membrane bound nucleus, and Golgi apparatus. Bacteria are simpler than other organisms, and single celled microbes.
Both bacteria and cyanobacteria reproduce through the asexual method either by binary fission in unicellular, multiple fission in colonial form or by spore formation, and fragmentation in filamentous species.
Diabetes is a degenrative disease which are non-communicable (cannot be spread)
In short, Your Answer is True
Hope this helps!
Answer:
- Only fMet-tRNA(fMet) can bind first to the P site in the ribosome. ( A )
- There are more than one tRNA with the 5' CAU 3' anticodon. ( B )
- The N-formyl group attached to methionine prevents fMet from entering interior positions in a polypeptide. ( D )
Explanation:
The statements that explains how N--formyl methionine (fMet) is only associated with the 5' AUG initiation codon and not with internal AUG codons, given that methionine in both cases in encoded by an AUG in the mRNA are :
Only fMet-tRNA(fMet) can bind first to the P site in the ribosome. ( A )
There are more than one tRNA with the 5' CAU 3' anticodon. ( B )
The N-formyl group attached to methionine prevents fMet from entering interior positions in a polypeptide. ( D )
While statement C is wrong.
Answer:
below
Explanation:
C. Mice would have more food but the rest of the animals would starve. This is an example of FAIR biodiversity. Sorry if this is wrong
