Answer:
Ss (male) × Ss (female)
Explanation:
This question involves a single gene coding for hair length in guinea pigs. Based on the information in this question, the allele for short hair (S) is dominant over the allele for long hair (s). This means that a guinea pig will only be phenotypically long-haired if the genotype is "ss".
According to this question, Two short-haired guinea pigs are mated several times. Out of the 100 offsprings produced by this cross, 25 of them have long hair (recessive). This means that the phenotypic ratio of this cross is 3 short hair : 1 long hair i.e. 100 - 25 = 75 short hair. 75/25 = 3/1 = 3:1
To produce this phenotypic ratio, the parents must both be heterozygous (Ss) for the hair length gene.
The answer is <span>Anaphase I separates homologous chromosomes and anaphase II separates sister chromatids into daughter cells.</span>
Meiosis is a cell division which results in the reduction of chromosome number by half - from diploid to haploid - in daughter cells. It consists of meiosis I and meiosis II. Meiosis I produces two haploid cells. Meiosis II is analogous to mitosis, so in total, meiosis results in four haploid cells. So, in meiosis, there are two anaphases - the anaphase I in meiosis I and the anaphase II in meiosis II.
<span>In anaphase I, the sister chromatids separate from each other to the opposite sides of the cells. In meiosis I there are 46 chromosomes in duplicate, which are present as pairs of sister chromatids. In anaphase of meiosis II, since the cell is haploid, there are 23 chromosomes in duplicate, which are present as sister chromatids.</span>