Question

Write an equation of the line that passes through the given points. (-2,8) and (1,2)

Answer 1

The answer is y= -1/2x-7

Answer 2

The slope-intercept form of the line that passes through the points (-2,8) and (1,2) is y=-2x+4

Step-by-step explanation:

Given:  

Points(x,y)= )= (-2,8)

Points(x1,y1)=  (1,2)

To find:

Equation in slope-intercept form=?

Solution:

The slope intercept form of a line is y= mx + b  

Where m= the slope

STEP 1: Finding the slope value

$\bold{\text { slope } =\frac{y-y 1}{x-x 1}}$

Substituting the points in the formula we get,  

$\text {slope, } \quad m=\frac{2-8}{1-(-2)}$

$\text {slope, } \quad m=\frac{-6}{3}$

$\text { slope, } \quad m=-2$

STEP 2: Finding the value of  b

Substituting the slope value in the equation we have

y=mx+b,

y= -2(x)+b

y= -2(x) + b

substituting x and y from the points given,

8=-2(-2) + b

8=4+b

8-4=b

b =4

STEP 3: Formation of slope intercept equation

Substituting b and m in the equation of slope we get,

y= mx + b  

y= -2x+4.