Please help! I will mark as brainliest IF answer is right. <3

Mathematics

1 answer:

pantera1 [17]3 years ago

8 0

Answer:

420/69

Step-by-step explanation:

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Which function is equivalent to the inverse of y=sec(x)

kipiarov [429]

From the identity:

$sec(x)= \frac{1}{cos(x)}$

$f(x)=sec(x)= \frac{1}{cos(x)}$

the inverse of f is g such that f(g(x))=x,

we must find g(x), such that $\frac{1}{cos[g(x)]}=x$

thus, $cos[g(x)]= \frac{1}{x}$

$g(x)=cos^{-1} (\frac{1}{x})$

Answer: b. g(x)=cos^-1(1/x)

6 0

3 years ago

A cruise ship is traveling south going approximately 22 mph when it hits the Gulf Stream flowing east at 4 mph. Which expression

alexira [117]

<h2>Hello!</h2>

The answer is:

The correct option is

a) $Resultant=\sqrt{22^{2} +4^{2} }$

Since a right triangle is formed, we can calculate the resultant force using the Pythagorean Theorem which states that:

$c=\sqrt{a^{2}+b^{2}}$

Where,

c, is the hypothenuse.

a, is one triangle leg.

b, is the other triangle leg.

So, we are given the information:

$a=22mph$

$b=4mph$

So, calculating the resultant force (hypothenuse), we have:

$Resultant=\sqrt{22^{2} +4^{2} }$

Hence, the expression that would find the result velocity is:

a) [tex]Resultant=\sqrt{22^{2} +4^{2} }[/tex]

Have a nice day!

4 0

3 years ago

3 On a coordinate grid, the location of a lighthouse is at L, and the location of a buoy is at B. At noon, a ship is at the midp

Zarrin [17]

Answer:

$(\frac{1}{2}, 2)$

Step-by-step explanation:

Using the midpoint formula, $M(\frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2})$ , we can find the coordinates that represents the position of the ship at noon.