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motikmotik
3 years ago
13

To prepare for a bake-off, Clarissa used 560 grams of flour each day for 3 weeks. How many kilograms did Clarissa use in those 3

weeks? 1 g = 0.001 kg
Mathematics
1 answer:
Sindrei [870]3 years ago
5 0
Convert G to kg
560/1000=.56 kg a day

If the bake off was 5 days
.56*5= 2.8kg... per week
2.8kg*3= 8.4 kg for 3 weeks

If it was 7 days
.56*7 = 3.92 kg per week
3.92*3= 11.76 kg for 3 weeks
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There are two different loci that cause white coat color in horses. One locus is the albino locus found in all mammals. Albinism
julsineya [31]

Answer: 6/12 are white, 3/12 are colored and 3/12 are albino.

Step-by-step explanation: If the horses are white and their parents are ccww (albino) and CCWw (white horse), according to Mendel's premises, they both must be CcWw, since the crossing provides one C from one parent and other c from the other parent, one W and the other w.  Using Mendel's chess and the principle of independent segregation, the crossing between CcWw results in the following fenotypical ratio:

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1/16 ccww (albino)

Excluding the 4 individuals that have the lethal locus, we have 6/12 that are white (2/12 + 4/12) and 3/12 (1/12 + 2/12) that are colored. Also, there are 3/12 of albino individuals as well.

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3 years ago
Root 3 cosec140° - sec140°=4<br>prove that<br><br>​
Lorico [155]

Answer:

Step-by-step explanation:

We are to show that \sqrt{3} cosec140^{0} - sec140^{0} = 4\\

<u>Proof:</u>

From trigonometry identity;

cosec \theta = \frac{1}{sin\theta} \\sec\theta = \frac{1}{cos\theta}

\sqrt{3} cosec140^{0} - sec140^{0} \\= \frac{\sqrt{3} }{sin140} - \frac{1}{cos140} \\= \frac{\sqrt{3}cos140-sin140 }{sin140cos140} \\

From trigonometry, 2sinAcosA = Sin2A

= \frac{\sqrt{3}cos140-sin140 }{sin140cos140} \\\\=  \frac{\sqrt{3}cos140-sin140 }{sin280/2}\\=  \frac{4(\sqrt{3}/2cos140-1/2sin140) }{2sin280}\\\\= \frac{4(\sqrt{3}/2cos140-1/2sin140) }{sin280}\\since sin420 = \sqrt{3}/2 \ and \ cos420 = 1/2  \\ then\\\frac{4(sin420cos140-cos420sin140) }{sin280}

Also note that sin(B-C) = sinBcosC - cosBsinC

sin420cos140 - cos420sin140 = sin(420-140)

The resulting equation becomes;

\frac{4(sin(420-140)) }{sin280}

= \frac{4sin280}{sin280}\\ = 4 \ Proved!

3 0
3 years ago
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