Credit. That's why the stock market crash was so terrible in 1929.
I believe it’s just the base, radius, and maybe the total surface
Hello from MrBillDoesMath!
Answer: Two solutions
Discussion:
Based on the graph provided the curves intersect at two point
Thank you,
MrB
Answer:
Not really, actually it depends on the shape given whether it's a rectangle, a square etc. Because you can't conclude that the shape of a rectangle with such dimensions could be guaranteed.
Answer:
<h2>The distance to the Eath's Horizon from point P is 352.8 mi, approximately.</h2>
Step-by-step explanation:
You observe the problem from a graphical perspective with the image attached.
Notice that side
is tangent to the circle, which means is perpendicular to the radius which is equal to 3,959 mi.
We have a right triangle, that means we need to use the Pythagorean's Theorem, to find the distance to the Earth's Horizon from point P.
The hypothenuse is 3959 + 15.6 = 3974.6 mi.

Therefore, the distance to the Eath's Horizon from point P is 352.8 mi, approximately.