F(x) = <br> sin 4x/2x<br> x-intercepts?

I need help when it comes to the elimation method, when one of the equations is in y=mx+b. For example.

user100 [1]

Answer:

x = 431/61; y = -239/61

Step-by-step explanation:

You need to add the two equations to eliminate one variable. If you add the equations as they are now, you will get 14x + y = 95, and as you can see, you still have two variables. You must make the coefficients of one of the variables additive inverses. That way, when you add the equations, one variable will be eliminated since its coefficients add to zero.

Let's work on eliminating y.

The first equation has 5y, and the second equation has -4y. If we multiply both sides of the first equation by 4, the y-term will become 20y. If we multiply both sides of the second equation by 5, the y-term of the second equation becomes -20y. The terms 20y and -20y will add to 0, and the y variable will be eliminated.

9x+5y=44

5x-4y=51

1) Multiply the both sides of the first equation by 4:

36x + 20y = 176

2) Multiply both sides of the second equation by 5:

25x - 20y = 255

3) Now add the equations:

61x + 0y = 431

61x = 431

Divide both sides by 61:

x = 431/61

Now that we know x, we can substitute y into one of the equations and solve for y. We can also start with the two original equations and do the appropriate multiplications and addition to eliminate x and solve for y.

I'll do elimination of x now, so you see elimination being used again.

Start with the original system again.

9x+5y=44

5x-4y=51

Multiply both sides of the first equation by -5. Multiply both sides of the second equation by 9.

-45x - 25y = -220

45x - 36y = 459

Now add the new equations.

0x - 61y = 239

-61y = 239

Divide both sides by -61:

y = -239/61

Solution: x = 431/61; y = -239/61

5 0

3 years ago

My little brother wants to know if these are equal 5(2j + 3 + j) = 3(5j + 4 + j)

balu736 [363]

Answer:

they are not equal to

Step-by-step explanation:

4 0

3 years ago

Jim's soccer team is making fruit baskets for a fundraiser. They have 88 peaches, 60 bananas, and 54 kiwis to use. If each baske

cluponka [151]

The greatest number of fruit baskets they can make is 2 with each one having 44 peaches, 30 bananas and 27 kiwis

<h3><u>Solution:</u></h3>

Jim’s fruit basket has 88 peaches, 60 bananas and 54 Kiwis to use.

If each basket have same number of each type, we have to determine the greatest number of fruit baskets they can make

We need to find greatest common factor of 88, 60 and 54

When we find all the factors of two or more numbers, and some factors are the same ("common"), then the largest of those common factors is the Greatest Common Factor.

<em><u>Greatest common factor of 88, 60 and 54:</u></em>

The factors of 54 are: 1, 2, 3, 6, 9, 18, 27, 54

The factors of 60 are: 1, 2, 3, 4, 5, 6, 10, 12, 15, 20, 30, 60

The factors of 88 are: 1, 2, 4, 8, 11, 22, 44, 88

Then the greatest common factor is 2

On dividing the number of fruits by 2 we get

$\begin{array}{l}{\text { Apples in each basket }=\frac{88}{2}=44} \\\\ {\text { Bananas in each basket }=\frac{60}{2}=30} \\\\ {\text { Kiwis in each basket }=\frac{54}{2}=27}\end{array}$

Hence, there can be 2 basket with each one having 44 peaches, 30 bananas and 27 kiwis

6 0

4 years ago

20) (8b-6+36) –<br> -76-3)

Dafna1 [17]

I think it’s 8b+103, I’m not sure.

5 0

3 years ago

It is given that 2(3 + x) = 6 + 2x. This is an example of the ___________ property.

Reptile [31]

Answer:

Distributive Property

Step-by-step explanation:

Here is the problem:

2(3 + x)

Here is the answer 6 + 2x

Method to solve it:

a(b+c) = ab + ac

Let's substitute numbers for letters:

2(3 + x)

2*3 = 6

2 * x = 2x

=

6 + 2x

Best Of Luck,

- I.A. -

4 0

3 years ago

F(x) = sin 4x/2x x-intercepts?