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levacccp [35]
4 years ago
9

Daniel's basic cell phone rate each month is $29.95. Add to that $5.95 for voice mail and $2.95 for text messaging. This past mo

nth Daniel spent an additional C dollars on long distance. His total bill was $62.35. How much did Daniel spend on long distance?
Mathematics
2 answers:
Vlad [161]4 years ago
8 0
5.95 + 2.95 = 8.9
8.9 + 29.95 = 38.85
62.35 - 38.85 = 23.5 
So Daniel spent $23.50 on long distance calling 
Korvikt [17]4 years ago
7 0

Answer: Daniel spent $23.5 on long distance

Step-by-step explanation:

Hi, to answer this question we have to write an equation with the information given.

So, Daniel's total bill (62.35) is equal to the sum of the cost of all the services: Basic cell phone rate (29.95); voice mail (5.95); text messaging (2.95); long distance (C)

Mathematically speaking:

29.95+5.95+2.95+C = 62.35

Solving for C

38.85+C =62.35

C =62.35-38.85

C =$23.5

Daniel spent $23.5 on long distance

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3 years ago
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pishuonlain [190]
Division is basically
x divided by y=x/y so
18 divided by 2/3=\frac{18}{ \frac{2}{3} }
we want the bottom number to be =1 so we multiply 2/3 by 3/2 to make it 1 (or 6/6=1), but we have to multiply the top number by 3/2 also so that we don't change the fraction and make our work useless so

\frac{18}{ \frac{2}{3} } times  \frac{ \frac{3}{2} }{ \frac{3}{2} } = \frac{ \frac{54}{2} }{ \frac{6}{6} }= \frac{27}{1}=27

the answe ris 27
6 0
3 years ago
Read 2 more answers
What is the variance of a portfolio invested 21 percent each in a and b and 58 percent in c?
victus00 [196]
Given the following information:

\begin{tabular}
{|p{1.5cm}|p{1.5cm}|p{1.2cm}|p{1.2cm}|p{1.2cm}|}
\multicolumn{1}{|p{1.5cm}|}{State of economy}\multicolumn{1}{|p{2.6cm}|}{Probability of State of economy}\multicolumn{3}{|p{4.8cm}|}{Rate of Return if State Occurs}\\[1ex] 
\multicolumn{1}{|p{1.5cm}|}{}\multicolumn{1}{|p{2.6cm}|}{}\multicolumn{1}{|c|}{Stock A}&StockB&Stock C\\[2ex]
\multicolumn{1}{|p{1.5cm}|}{Boom}\multicolumn{1}{|p{2.6cm}|}{0.66}\multicolumn{1}{|p{1.27cm}|}{0.09}&0.03&0.34\\
\end{tabular}
\begin{tabular}
{|p{1.5cm}|p{1.5cm}|p{1.2cm}|p{1.2cm}|p{1.2cm}|}
\multicolumn{1}{|p{1.5cm}|}{Bust}\multicolumn{1}{|p{2.6cm}|}{0.34}\multicolumn{1}{|p{1.27cm}|}{0.23}&0.29&-0.14\\
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Part A:

The expected return on an equally weighted portfolio of these three stocks is given by:

0.66[0.33 (0.09) + 0.33 (0.03) + 0.33(0.34)] \\ +0.34[0.33 (0.23) + 0.33(0.29) +0.33(-0.14)] \\  \\ =0.66(0.0297 + 0.0099 + 0.1122)+0.34(0.0759+0.0957-0.0462) \\  \\ =0.66(0.1518)+0.34(0.1254)=0.1002+0.0426=0.1428=\bold{14.28\%}



Part B:

Value of a portfolio invested 21 percent each in A and B and 58 percent in C is given by

For boom: 0.21(0.09) + 0.21(0.03) + 0.58(0.34) = 0.0189 + 0.0063 + 0.1972 = 0.2224 or 22.24%.

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0.66(0.2224-0.1563)^2+0.34(0.028-0.1563)^2 \\  \\ =0.66(0.0661)^2+0.34(-0.1283)^2=0.66(0.00437)+0.34(0.01646) \\  \\ =0.00288+0.0056=\bold{0.00848}
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Answer:

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Step-by-step explanation:

The formula that is used to find arc length is:

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