2(x-5)=2x+3
2x-10=2x+3
2x=2x+13
0x=13
x=0
There are no solutions (13/0 is 0)
We know that pupils are students
Students = S
boys = B
Teachers = T
So....
S = 8T
Boys = 3G
T = B - 70
Since there is 8x students than teachers, I did Boys = 6x and girls = 2x
I'm going to use this next: S = 8T
8x = 8(B -70)
8x = 8(6x - 70)
8x = 4x - 560
x = 14
We know there is 8x students, so there are 112 students and we know that there is 1/8 of teachers, so there are 14 teachers.
Answer = 126.
You multiply 24 by 6 to get C. $144
it is 1/6 that is the anwser
Answer:
(-4, 5)
Step-by-step explanation:
The problem is a system of equations where you have two variables and can use the method of eliminate (eliminating one of the variables) to solve. In this case, you will need to multiply one of the fractions by a factor to eliminate a variable. It seems easiest to multiply the first equation by a factor of -5:
-5(x - 3y) = -24 (distribute) -5x + 15y = 120
Add the equations:
-5x + 15y = 120
<u>+5x + 8y = -5</u>
23y = 115 (divide by 23)
y = 5
Solve for 'x': x - 3(5) = -24 or x - 15 = 24 (add 15) x = -4
Ordered pair: (-4, 5)
