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notka56 [123]
3 years ago
6

Peyton Manning threw for 1,126 yards in his first four games. At this rate, how many yards will he throw for in sixteen games?

Mathematics
1 answer:
dimaraw [331]3 years ago
4 0
The answer 4504 yards. You divide 1126 by 4 then multiply that answer by 16.
You might be interested in
PLEASE HELP!!!!! Geometry
devlian [24]

Answer:

P = 49°

R = 131°

Q = 114°

S = 66°

Step-by-step explanation:

in a quadrilateral inscribed in a circle, the opposite angles are always supplementary, meaning they add up to 150

we are given opposite angles P and R (S is not given so we can't use Q and S)

P+R = 180

5y+14 + 15y + 26 = 180

20y + 40 = 180

20y = 140

y = 7

so...

P = 5(7) + 14 = 35 + 14 = 49

R = 180-49 (since opposite angles in inscribed quadrilaterals are supplementary) = 131

Q = (7)^2 + 65 = 49 + 65 = 114

S = 180-114 = 66

8 0
3 years ago
Use a Venn diagram to answer the question. A survey of 180 families showed that 67 had a​ dog; 52 had a​ cat; 22 had a dog and a
Mice21 [21]

Answer:

There are 13 families had a parakeet only

Step-by-step explanation:

* Lets explain the problem

- There are 180 families

- 67 families had a dog

- 52 families had a cat

- 22 families had a dog and a cat

- 70 had neither a cat nor a​ dog, and in addition did not have a​

 parakeet

- 4 had a​ cat, a​ dog, and a parakeet (4 is a part of 22 and 22 is a part

 of 67 and 520

* We will explain the Venn-diagram

- A rectangle represent the total of the families

- Three intersected circles:

 C represented the cat

 D represented the dog

 P represented the parakeet

- The common part of the three circle had 4 families

- The common part between the circle of the cat and the circle of the

 dog only had 22 - 4 = 18 families

- The common part between the circle of the dog and the circle of the

 parakeet only had a families

- The common part between the circle of the cat and the circle of the

 parakeet only had b families

- The non-intersected part of the circle of the dog had 67 - 22 - a =

  45 - a families

  had dogs only

- The non-intersected part of the circle of the cat had 52 - 22 - b =  

  30 - b families

  had cats only

- The non-intersected part of the circle of the parakeet had c families

  had parakeets only

- The part out side the circles and inside the triangle has 70 families

- Look to the attached graph for more under stand

∵ The total of the families is 180

∴ The sum of all steps above is 180

∴ 45 - a + 18 + 4 + 30 - b + b + c + a + 70 = 180 ⇒ simplify

- (-a) will cancel (a) and (-b) will cancel (b)

∴ (45 + 18 + 4 + 30 + 70) + (-a + a) + (-b + b) + c = 180

∴ 167 + c = 180 ⇒ subtract 167 from both sides

∴ c = 180 - 167 = 13 families

* There are 13 families had a parakeet only

5 0
3 years ago
6 + (4+9) =19 Rewrite using the Associative Property
maw [93]

5*4*6=120
4+(6+9)=19
675+9=75
8 0
3 years ago
Please i’m not good at math i need help i’m doing summer school online and i need help
Sati [7]

Answer:

135

____________

2*25/5=10

100*5=500

15*5=75

75*5=375

10+500-375=135

Hope this helps :3

8 0
3 years ago
I have to factor this : 7x2+35x-49 <br> im not sure what to do.
Anon25 [30]
7(x^2 +5x-7) 
i think this is how it works
4 0
3 years ago
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