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love history [14]
3 years ago
14

5, 7, 11, 15, 21 is an infinite series. True or False

Mathematics
1 answer:
Gekata [30.6K]3 years ago
8 0

Answer:

True

Step-by-step explanation:

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I need help d:<br> Thank you plz
sladkih [1.3K]
For question<span> </span> 111. the value of x is x = 2/5 

Sorry I couldn't answer other questions.. :(

But I hope this helped!!… :D
Please correct me if I'm wrong!!… :3

4 0
3 years ago
Read 2 more answers
Suppose a Ferris Wheel is 160 feet high and casts a shadow that is 64 feet long. At the same time, a ticket booth next to the fe
const2013 [10]
I think the ticket booth would be 7 feet high. 160/64 = 2.5. 2.8 x 2.5 = 7
7 0
2 years ago
Is 4.50 an irrational or rational number?
andre [41]
It is irrational because rational numbers are whole and irrational numbers are decimals,fractions,negatives,and mixed numbers also irrational numbers go on and on forever rational stops for example  3 is rational and 9.6 is irrational 4.50 is irrational hope this helps you i hope i am the brainliest answer because i need it for the next rank 

4 0
3 years ago
0.000034 into scientific notation
Rainbow [258]

Answer:

3.4 x 10^-5

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
A new medical test has been designed to detect the presence of the mysterious Brainlesserian disease. Among those who have the d
astra-53 [7]

Answer:

Step-by-step explanation:

The persons who have diseases = 19%

The persons who do not have diseases = 81%

Probability for the test showing positive = Prob of actual disease and shows positive + Prob of no disease but test shows wrong

= 0.7*0.19+0.04*0.81\\=0.133+0.0324\\=0.1654

Prob that the person actually has the disease given that the test administered to an individual is positive= \frac{0.133}{0.1654} \\=0.0804

30) A    B   C   total

    2x  7x   x      10x

P(A) = 0.2, P(B) = 0.7, P(C) = 0.1

Let D be the event that the product is defective

P(D/A) = 0.032, P(D/B) = 0.034 and P(D/C) = 0.056

Required probability =P(C/D)

= \frac{P(D/C) P(C)}{P(D/A) P(a)+P(D/B) P(B)+P(D/C) P(C)}

by using Bayes theorem for conditional probability

= \frac{0.1*0.056}{0.2*0.032+0.7*0.034+0.1*0.056} \\=\frac{0.0056}{0.0064+0.0238+0.0056} \\\\=0.156425

32) 7 digit phone numbers with repitition including 0 will be

= 10^7

Numbers which have atleast one 7 = total number - numbers which do not have a single 7

= 10^7 -9^7

the probability that a 7-digit phone number contains at least one 7

=\frac{10^7-9^7}{10^7}

3 0
2 years ago
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