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Alborosie
3 years ago
13

Simon calculated the volume of the prism. His work is shown here. area of base = B = 1 2 bh = 1 2 (5)(13) = 32.5 m2 volume = Bh

= 32.5(12) = 390 m3 A triangular prism. The triangular base has a base of 5 meters and height of 12 meters. The height is 4 meters. What errors did he make? Check all that apply.

Mathematics
1 answer:
melamori03 [73]3 years ago
4 0

Answer:

Options (1) and (5) are the correct options.

Step-by-step explanation:

See attachment for the complete question.

Simon's work,

Area of the base = B =\frac{1}{2}bh = \frac{1}{2}(5)(13)=32.5 m²

Volume = Bh = 32.5(12) = 390 m³

Let's check the error's he made.

Area of the base of the triangular prism

B =\frac{1}{2}bh=\frac{1}{2}(5)(12)

B = 30 m²

Volume of the prism = (Area of the triangular base)×(Height)

V = 30 × 4

V = 120 m³

Therefore, Options (1) and (5) are the correct options.

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Answer:

Step-by-step explanation:

Hello!

There are 4 3D printers available to print drone parts, then be "Di" the event that the printer i printed the drone part (∀ i= 1,2,3,4), and the probability of a randomly selected par being print by one of them is:

D1 ⇒ P(D1)= 0.15

D2 ⇒ P(D2)= 0.25

D3 ⇒ P(D3)= 0.40

D4 ⇒ P(D4)= 0.20

Additionally, there is a chance that these printers will print defective parts. Be "Ei" represent the error rate of each print (∀ i= 1,2,3,4) then:

P(E1)= 0.01

P(E2)= 0.02

P(E3)= 0.01

P(E4)= 0.02

Ei is then the event that "the piece was printed by Di" and "the piece is defective".

You need to determine the probability of randomly selecting a defective part printed by each one of these printers, i.e. you need to find the probability of the part being printed by the i printer given that is defective, symbolically: P(DiIE)

Where "E" represents the event "the piece is defective" and its probability represents the total error rate of the production line:

P(E)= P(E1)+P(E2)+P(E3)+P(E4)= 0.01+0.02+0.01+0.02= 0.06

This is a conditional probability and you can calculate it as:

P(A/B)= \frac{P(AnB)}{P(B)}

To reach the asked probability, first, you need to calculate the probability of the intersection between the two events, that is, the probability of the piece being printed by the Di printer and being defective Ei.

P(D1∩E)= P(E1)= 0.01

P(D2∩E)= P(E2)= 0.02

P(D3∩E)= P(E3)= 0.01

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P(D2/E)= \frac{P(E2)}{P(E)} = \frac{0.02}{0.06}= 0.33

P(D3/E)= \frac{P(E3)}{P(E)} = \frac{0.01}{0.06}= 0.17

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I hope this helps!

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