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ahrayia [7]
3 years ago
14

7(-2k+4)-6=7k-20 what is the answer

Mathematics
1 answer:
lord [1]3 years ago
7 0
The answer to this equation would be k=2
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What are the values of a and b in the equation a[3x-8]=b-18x
3241004551 [841]
A(3x-8)=0

a=0 and x=8/3

This second line is not necessarily true. We could have a=0 OR x=8/3. They don't both have to be 0. a(3x-8)=b-18x

No solutions found

Rearrange:

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

a*(3*x-8)-(b-18*x)=0

Step by step solution :

Step 1 :

Equation at the end of step 1 :

a • (3x - 8) - (b - 18x) = 0
Step 2 :

Equation at the end of step 2 :

3ax - 8a + 18x - b = 0
Step 3 :

Solving a Single Variable Equation :

3.1 Solve 3ax-8a+18x-b = 0
3 0
4 years ago
Please help quick!! pythagorean theorem!
Ivahew [28]

Answer:

hmmmmm not sure

Step-by-step explanation:

8 0
3 years ago
The line AB has midpoint (-2, 4).<br>A has coordinates (3,-2).<br>Find the coordinates of B.​
worty [1.4K]

Answer: B(8, -8 )

Step-by-step explanation: The formula for calculating mid - point between two points is given as :

M = ( \frac{x_{1}+x_{2}}{2} , \frac{y_{1}+y_{2}}{2} )

The mid point has been given from the question .

x_{1} = -2

x_{2} = ?

y_{1} = 4

y_{2} = ?

substituting into the formula , we have

(3 , - 2 ) = (\frac{-2+x_{2}}{2} , \frac{4+y_{2}}{2} )

Equating x -component to x and y component to y , we have

3 = \frac{-2+x_{2}}{2}

cross multiplying , we have

6 = -2 + x_{2}

Therefore:

x_{2} = 8

Also , equating y component to y , we have

-2 = \frac{4+y_{2}}{2}

-4 = 4 + y_{2}

y_{2} = -8

Therefore :

x_{2}  = 8

y_{2}  = -8

check

-2 + 8 / 2 = 3 and

-8 + 4 / 2 = -2

4 0
4 years ago
Plz explain how to do this
LUCKY_DIMON [66]
Here is the definition of a negative exponent.

For any non-zero value of a,

a^{-n} = \dfrac{1}{a^n}

Look at your problem and follow the definition.

4^{-3} = \dfrac{1}{4^3}

Since 4^3 = 4 * 4 * 4 = 64, we can now write:

4^{-3} = \dfrac{1}{4^3} = \dfrac{1}{4 \times 4 \times 4} = \dfrac{1}{64}
4 0
4 years ago
What is the y-intercept of the function y = negative one-half cosine (three-halves x)?
Jet001 [13]
A. Sorry if I’m wrong
3 0
3 years ago
Read 2 more answers
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